Authorisation Object for Organizational Unit.

Hi Experts
I have an query on user authorisation as follow,
As in my project I have two user as Maker & Checker. Maker is having Business Area B001 Authorisation and in checker is also having the different role with same Business area authorisation, Now my query is I wanted to sort this on Organisational Unit level. So is there any object available for to assign Org Unit level Authorasation. as like P_Origin is there in SAP sytem.. please guide me ...
Regards
Swapnil

Hi Swapnil,
You can use HR Master Data Customer-Specific object to include any fields from infotype 0001 to authorisation checks. Please check the |help.sap.com (http://help.sap.com/erp2005_ehp_02/helpdata/en/4e/74ba3bd14a6a6ae10000000a114084/frameset.htm) regarding use of this object. On the bottom of that page is a link for creating the object and activating the check against it.
Regards,
Saku

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    Hi,
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    We create ROLES and assign the Authorization and TCODES for that role, so only that user can have access to those T Codes.
    USe SUIM and SU21 T codes for this.
    Much of the data in an R/3 system has to be protected so that unauthorized users cannot access it. Therefore the appropriate authorization is required before a user can carry out certain actions in the system. When you log on to the R/3 system, the system checks in the user master record to see which transactions you are authorized to use. An authorization check is implemented for every sensitive transaction.
    If you wish to protect a transaction that you have programmed yourself, then you must implement an authorization check.
    This means you have to allocate an authorization object in the definition of the transaction.
    For example:
    program an AUTHORITY-CHECK.
    AUTHORITY-CHECK OBJECT <authorization object>
    ID <authority field 1> FIELD <field value 1>.
    ID <authority field 2> FIELD <field value 2>.
    ID <authority-field n> FIELD <field value n>.
    The OBJECT parameter specifies the authorization object.
    The ID parameter specifies an authorization field (in the authorization object).
    The FIELD parameter specifies a value for the authorization field.
    The authorization object and its fields have to be suitable for the transaction. In most cases you will be able to use the existing authorization objects to protect your data. But new developments may require that you define new authorization objects and fields.
    http://help.sap.com/saphelp_nw04s/helpdata/en/52/67167f439b11d1896f0000e8322d00/content.htm
    To ensure that a user has the appropriate authorizations when he or she performs an action, users are subject to authorization checks.
    Authorization : An authorization enables you to perform a particular activity in the SAP System, based on a set of authorization object field values.
    You program the authorization check using the ABAP statement AUTHORITY-CHECK.
    AUTHORITY-CHECK OBJECT 'S_TRVL_BKS'
    ID 'ACTVT' FIELD '02'
    ID 'CUSTTYPE' FIELD 'B'.
    IF SY-SUBRC <> 0.
    MESSAGE E...
    ENDIF.
    'S_TRVL_BKS' is a auth. object
    ID 'ACTVT' FIELD '02' in place 2 you can put 1,2, 3 for change create or display.
    The AUTHORITY-CHECK checks whether a user has the appropriate authorization to execute a particular activity.
    This Authorization concept is somewhat linked with BASIS people.
    As a developer you may not have access to access to SU21 Transaction where you have to define, authorizations, Objects and for nthat object you assign fields and values. Another Tcode is PFCG where you can assign these authrization objects and TCodes for a  profile and that profile in turn attached to a particular user.
    Take the help of the basis Guy and create and use.
    Sy-SUBRC values
    4              User has no authorization in the SAP System for
                   such an action. If necessary, change the user
                   master record.
    8              Too many parameters (fields, values). Maximum
                   allowed is 10.
    12             Specified object not maintained in the user
                   master record.
    16             No profile entered in the user master record.
    24             The field names of the check call do not match
                   those of an authorization. Either the
                   authorization or the call is incorrect.
    28             Incorrect structure for user master record.
    32             Incorrect structure for user master record.
    36             Incorrect structure for user master record.
    http://www.sap.ittoolbox.com/groups/technical-functional/sap-basis/please-how-to-create-an-authorization-object-386391 - 78k -
    http://www.sap-abaprogram.blogspot.com/2007/11/what-is-use-of-
    authorization-checks-to.html - 75k -
    www.sapworld.hpg.ig.com.br/download/ab4query.pdf
    with thanks,
    Abaper.

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    Question is solved.
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    M_EINK_FRG Release Code and Group (Purchasing)
    FRGGR      Release group
    Regards,
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  • Hierarchical + Analytical query for organizational unit parameters

    Hello gurus,
    I try for a couples of hour ago to make a query work as I would like.
    Our application need to store some parameters for our organization units. These organization units are typically organized in in an hierarchy manner: one top unit with many level of child units. The parameters are stored into another table with 1:1 relationship.
    For sake of visualisation, here is the data for the organization unit and parameter table in a more visual format:
    SQL> select * from organization_unit;
    UNIT_CODE  UNIT_NAME            PARENT_UNIT_CODE
    00000      Top level
    10         L2 unit #10          00000
    10-01      L3 unit #10-01       10
    10-02      L3 unit #10-02       10
    20         L2 unit #20          00000
    20-01      L3 unit #20-01       20
    20-02      L3 unit #20-02       20
    SQL>  select * from org_unit_parameters;
    UNIT_CODE  PARAM1               PARAM2               PARAM3               PARAM4
    00000      Default value        Default value        Default value        {null}
    10         {null}               Value from 10        Value from 10        {null}
    10-01      {null}               {null}               Value from 10-01     {null}
    10-02      {null}               {null}               {null}               Value from 10-02
    20         Value from 20        Value from 20        Value from 20        {null}
    20-01      {null}               Value from 20-01     {null}               {null}
    20-02      {null}               Value from 20-02     {null}               {null}The application will query the parameter table to get a parameter value for a given unit.
    The parameter resolution algorithm is rather simple: when querying a unit, the applicable parameter is the one defined at the requested level. If the parameter is not defined (null) at the requested level, the parameter value that must be returned is the next defined one in the parent hierarchy. In some rare cases, it can be null if a parameter is not defined anywhere from the requested level to top.
    I've made a query that seems to work when querying for one unit at a time. It use hierarchical operators (start with + connect by) with a bit of analytical functions. Here is a test & raw output example:
    SQL> WITH hierarchy
      2  AS
      3  (
      4    SELECT ou.unit_code,
      5         LEVEL            AS lvl
      6    FROM   organization_unit ou
      7    START WITH
      8      ou.unit_code = '20-01'
      9    CONNECT BY
    10      ou.unit_code = PRIOR ou.parent_unit_code
    11  )
    12  SELECT h.*,
    13       p.param1                                                        AS param1_raw,
    14       LAST_VALUE (p.param1 IGNORE NULLS) OVER (ORDER BY h.lvl DESC)   AS param1_with_last,
    15       FIRST_VALUE(p.param1 IGNORE NULLS) OVER (ORDER BY h.lvl ASC)    AS param1_with_first,
    16       p.param2                                                        AS param2_raw,
    17       LAST_VALUE (p.param2 IGNORE NULLS) OVER (ORDER BY h.lvl DESC)   AS param2_with_last,
    18       FIRST_VALUE(p.param2 IGNORE NULLS) OVER (ORDER BY h.lvl ASC)    AS param2_with_first,
    19       p.param3                                                        AS param3_raw,
    20       LAST_VALUE (p.param3 IGNORE NULLS) OVER (ORDER BY h.lvl DESC)   AS param3_with_last,
    21       FIRST_VALUE(p.param3 IGNORE NULLS) OVER (ORDER BY h.lvl ASC)    AS param3_with_first,
    22       p.param4                                                        AS param4_raw,
    23       LAST_VALUE (p.param4 IGNORE NULLS) OVER (ORDER BY h.lvl DESC)   AS param4_with_last,
    24       FIRST_VALUE(p.param4 IGNORE NULLS) OVER (ORDER BY h.lvl ASC)    AS param4_with_first
    25  FROM   hierarchy                                h
    26         LEFT JOIN org_unit_parameters         p
    27         ON h.unit_code = p.unit_code
    28  ORDER BY h.lvl DESC;
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    00000         3 Default value        Default value        Value from 20        Default value        Default value        Value from 20-01     Default value        Default value        Value from 20        {null}               {null}               {null}
    20            2 Value from 20        Value from 20        Value from 20        Value from 20        Value from 20        Value from 20-01     Value from 20        Value from 20        Value from 20        {null}               {null}               {null}
    20-01         1 {null}               Value from 20        {null}               Value from 20-01     Value from 20-01     Value from 20-01     {null}               Value from 20        {null}               {null}               {null}               {null}Seems pretty good, the upper parameters are well «propagated» down with LAST_VALUE function. But, I don't understand why the use of FIRST_VALUE and oppposite ordering doesn't give the same result. A little more playing with the last query for getting the final result for a given unit code:
    SQL> SELECT *
      2  FROM
      3  (
      4     WITH hierarchy
      5     AS
      6     (
      7        SELECT ou.unit_code,
      8               LEVEL            AS lvl
      9        FROM   organization_unit ou
    10        START WITH
    11           ou.unit_code = '20-01'
    12        CONNECT BY
    13           ou.unit_code = PRIOR ou.parent_unit_code
    14     )
    15     SELECT h.*,
    16            LAST_VALUE (p.param1 IGNORE NULLS) OVER (ORDER BY h.lvl DESC)   AS param1,
    17            LAST_VALUE (p.param2 IGNORE NULLS) OVER (ORDER BY h.lvl DESC)   AS param2,
    18            LAST_VALUE (p.param3 IGNORE NULLS) OVER (ORDER BY h.lvl DESC)   AS param3,
    19            LAST_VALUE (p.param4 IGNORE NULLS) OVER (ORDER BY h.lvl DESC)   AS param4
    20     FROM   hierarchy                                h
    21               LEFT JOIN org_unit_parameters         p
    22               ON h.unit_code = p.unit_code
    23     ORDER BY h.lvl
    24  )
    25  WHERE ROWNUM = 1;
    UNIT_CODE   LVL PARAM1               PARAM2               PARAM3               PARAM4
    20-01         1 Value from 20        Value from 20-01     Value from 20        {null}Works well!
    But, my ultimate goal is to create a view that resolve correctly all these parameters for each level of the organization with proper propagation rather then querying for each unit at a time. I played a bit, but without success. :( My current raw query is this one:
    SQL> WITH hierarchy
      2  AS
      3  (
      4     SELECT ou.unit_code,
      5            LPAD(' ',2*(LEVEL-1)) || ou.unit_code    AS tree,
      6            LEVEL                                    AS lvl
      7     FROM   organization_unit ou
      8     START WITH
      9        parent_unit_code IS NULL
    10     CONNECT BY
    11        PRIOR unit_code =  parent_unit_code
    12  )
    13  SELECT h.*,
    14         p.param1                                                        AS param1_raw,
    15         LAST_VALUE (p.param1 IGNORE NULLS) OVER (ORDER BY h.lvl DESC)   AS param1_with_last,
    16         FIRST_VALUE(p.param1 IGNORE NULLS) OVER (ORDER BY h.lvl ASC)    AS param1_with_first,
    17         p.param2                                                        AS param2_raw,
    18         LAST_VALUE (p.param2 IGNORE NULLS) OVER (ORDER BY h.lvl DESC)   AS param2_with_last,
    19         FIRST_VALUE(p.param2 IGNORE NULLS) OVER (ORDER BY h.lvl ASC)    AS param2_with_first,
    20         p.param3                                                        AS param3_raw,
    21         LAST_VALUE (p.param3 IGNORE NULLS) OVER (ORDER BY h.lvl DESC)   AS param3_with_last,
    22         FIRST_VALUE(p.param3 IGNORE NULLS) OVER (ORDER BY h.lvl ASC)    AS param3_with_first,
    23         p.param4                                                        AS param4_raw,
    24         LAST_VALUE (p.param4 IGNORE NULLS) OVER (ORDER BY h.lvl DESC)   AS param4_with_last,
    25         FIRST_VALUE(p.param4 IGNORE NULLS) OVER (ORDER BY h.lvl ASC)    AS param4_with_first
    26  FROM   hierarchy                          h
    27            LEFT JOIN org_unit_parameters   p
    28            ON h.unit_code = p.unit_code
    29  ORDER BY h.unit_code;
    UNIT_CODE  TREE        LVL PARAM1_RAW                PARAM1_WITH_LAST          PARAM1_WITH_FIRST      PARAM2_RAW                   PARAM2_WITH_LAST          PARAM2_WITH_FIRST         PARAM3_RAW                PARAM3_WITH_LAST          PARAM3_WITH_FIRST         PARAM4_RAW                PARAM4_WITH_LAST       PARAM4_WITH_FIRST
    00000      00000         1 Default value             Default value             Default value          Default value                Default value             Default value             Default value             Default value             Default value             {null}                    Value from 10-02       {null}
    10           10          2 {null}                    Value from 20             Default value          Value from 10                Value from 10             Default value             Value from 10             Value from 10             Default value             {null}                    Value from 10-02       {null}
    10-01          10-01     3 {null}                    {null}                    Default value          {null}                       Value from 20-02          Default value             Value from 10-01          Value from 10-01          Default value             {null}                    Value from 10-02       Value from 10-02
    10-02          10-02     3 {null}                    {null}                    Default value          {null}                       Value from 20-02          Default value             {null}                    Value from 10-01          Default value             Value from 10-02          Value from 10-02       Value from 10-02
    20           20          2 Value from 20             Value from 20             Default value          Value from 20                Value from 10             Default value             Value from 20             Value from 10             Default value             {null}                    Value from 10-02       {null}
    20-01          20-01     3 {null}                    {null}                    Default value          Value from 20-01             Value from 20-02          Default value             {null}                    Value from 10-01          Default value             {null}                    Value from 10-02       Value from 10-02
    20-02          20-02     3 {null}                    {null}                    Default value          Value from 20-02             Value from 20-02          Default value             {null}                    Value from 10-01          Default value             {null}                    Value from 10-02       Value from 10-02As you can see, it's not as I expected. I know there's something to do with a PARTITION BY clause, but don't know how.
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    For reproductibility purposes, here is the code to create sturcture and data:
    Here is the format of my tables and some samble data:
    CREATE TABLE organization_unit (
       unit_code         VARCHAR2(5 CHAR)   NOT NULL PRIMARY KEY,
       unit_name         VARCHAR2(100 CHAR) NOT NULL,
       parent_unit_code  VARCHAR2(5 CHAR)  
    CREATE TABLE org_unit_parameters (
       unit_code         VARCHAR2(5 CHAR)   NOT NULL PRIMARY KEY,
       param1            VARCHAR2(100 CHAR),
       param2            VARCHAR2(100 CHAR),
       param3            VARCHAR2(100 CHAR),
       param4            VARCHAR2(100 CHAR)
    -- Inserting data
    INSERT INTO organization_unit (unit_code, unit_name, parent_unit_code)
    VALUES ('00000', 'Top level', NULL);
    INSERT INTO organization_unit (unit_code, unit_name, parent_unit_code)
    VALUES ('10', 'L2 unit #10', '00000');
    INSERT INTO organization_unit (unit_code, unit_name, parent_unit_code)
    VALUES ('10-01', 'L3 unit #10-01', '10');
    INSERT INTO organization_unit (unit_code, unit_name, parent_unit_code)
    VALUES ('10-02', 'L3 unit #10-02', '10');
    INSERT INTO organization_unit (unit_code, unit_name, parent_unit_code)
    VALUES ('20', 'L2 unit #20', '00000');
    INSERT INTO organization_unit (unit_code, unit_name, parent_unit_code)
    VALUES ('20-01', 'L3 unit #20-01', '20');
    INSERT INTO organization_unit (unit_code, unit_name, parent_unit_code)
    VALUES ('20-02', 'L3 unit #20-02', '20');
    INSERT INTO ORG_UNIT_PARAMETERS (unit_code, param1, param2, param3)
    VALUES ('00000', 'Default value', 'Default value', 'Default value');
    INSERT INTO ORG_UNIT_PARAMETERS (unit_code, param2, param3)
    VALUES ('10', 'Value from 10', 'Value from 10');
    INSERT INTO ORG_UNIT_PARAMETERS (unit_code, param3)
    VALUES ('10-01', 'Value from 10-01');
    INSERT INTO ORG_UNIT_PARAMETERS (unit_code, param4)
    VALUES ('10-02', 'Value from 10-02');
    INSERT INTO ORG_UNIT_PARAMETERS (unit_code, param1, param2, param3)
    VALUES ('20', 'Value from 20', 'Value from 20', 'Value from 20');
    INSERT INTO ORG_UNIT_PARAMETERS (unit_code, param2)
    VALUES ('20-01', 'Value from 20-01');
    INSERT INTO ORG_UNIT_PARAMETERS (unit_code, param2)
    VALUES ('20-02', 'Value from 20-02');
    COMMIT;

    Now, I hoppe I got your reqs:
    WITH hierarchy AS (
                       SELECT  ou.unit_code,
                               LPAD(' ',2*(LEVEL-1)) || ou.unit_code    AS tree,
                               LEVEL                                    AS lvl,
                               param1                                   AS param1_raw,
                               param2                                   AS param2_raw,
                               param3                                   AS param3_raw,
                               param4                                   AS param4_raw,
                               SYS_CONNECT_BY_PATH(p.param1,'#') || '#' AS param1_path,
                               SYS_CONNECT_BY_PATH(p.param2,'#') || '#' AS param2_path,
                               SYS_CONNECT_BY_PATH(p.param3,'#') || '#' AS param3_path,
                               SYS_CONNECT_BY_PATH(p.param4,'#') || '#' AS param4_path
                         FROM  organization_unit ou LEFT JOIN org_unit_parameters p
                                 ON ou.unit_code = p.unit_code
                         START WITH parent_unit_code IS NULL
                         CONNECT BY PRIOR ou.unit_code =  parent_unit_code
    SELECT  unit_code,
            tree,
            lvl,
            param1_raw,
            REGEXP_SUBSTR(param1_path,'[^#]+',1,GREATEST(1,REGEXP_COUNT(param1_path,'[^#]+'))) AS param1_with_last,
            REGEXP_SUBSTR(param1_path,'[^#]+')                                                 AS param1_with_first,
            param2_raw,
            REGEXP_SUBSTR(param2_path,'[^#]+',1,GREATEST(1,REGEXP_COUNT(param2_path,'[^#]+'))) AS param2_with_last,
            REGEXP_SUBSTR(param2_path,'[^#]+')                                                 AS param2_with_first,
            param3_raw,
            REGEXP_SUBSTR(param3_path,'[^#]+',1,GREATEST(1,REGEXP_COUNT(param3_path,'[^#]+'))) AS param3_with_last,
            REGEXP_SUBSTR(param3_path,'[^#]+')                                                 AS param3_with_first,
            param4_raw,
            REGEXP_SUBSTR(param4_path,'[^#]+',1,GREATEST(1,REGEXP_COUNT(param4_path,'[^#]+'))) AS param4_with_last,
            REGEXP_SUBSTR(param4_path,'[^#]+')                                                 AS param4_with_first
      FROM  hierarchy
      ORDER BY unit_code
    UNIT_ TREE              LVL PARAM1_RAW       PARAM1_WITH_LAST PARAM1_WITH_FIRS PARAM2_RAW       PARAM2_WITH_LAST PARAM2_WITH_FIRS PARAM3_RAW       PARAM3_WITH_LAST PARAM3_WITH_FIRS PARAM4_RAW       PARAM4_WITH_LAST PARAM4_WITH_FIRS
    00000 00000               1 Default value    Default value    Default value    Default value    Default value    Default value    Default value    Default value    Default value
    10      10                2                  Default value    Default value    Value from 10    Value from 10    Default value    Value from 10    Value from 10    Default value
    10-01     10-01           3                  Default value    Default value                     Value from 10    Default value    Value from 10-01 Value from 10-01 Default value
    10-02     10-02           3                  Default value    Default value                     Value from 10    Default value                     Value from 10    Default value    Value from 10-02 Value from 10-02 Value from 10-02
    20      20                2 Value from 20    Value from 20    Default value    Value from 20    Value from 20    Default value    Value from 20    Value from 20    Default value
    20-01     20-01           3                  Value from 20    Default value    Value from 20-01 Value from 20-01 Default value                     Value from 20    Default value
    20-02     20-02           3                  Value from 20    Default value    Value from 20-02 Value from 20-02 Default value                     Value from 20    Default value
    7 rows selected.
    SQL>  SY.
    Edited by: Solomon Yakobson on Nov 12, 2010 10:09 AM

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