Help on Select sum

Question

I have table
id order start end sum(a) sum(b)
1 1 0 0.1
1 2 0 0.2
1 3 0 0.3
2 1 0 1
2 2 0 2
2 3 0 3
What I need is as follows
id order start end sum(a) sum(b)
1 1 0 0.1 0 0.1
1 2 0 0.2 0.1 (0.1+0.2)
1 3 0 0.3 0.3 0.3+0.3
2 1 0 1 0 1
2 2 0 2 1 3
2 3 0 3 3 6
Thanks

Answer 1

I want to update table with new values
Can you help
SQL> create table mytable
  2  ( id number
  3  , ordering number
  4  , startvalue number
  5  , endvalue number
  6  , sum_a number
  7  , sum_b number
  8  )
  9  /
Tabel is aangemaakt.
SQL> insert into mytable (id,ordering,startvalue,endvalue)
  2  select 1 id, 1 ordering, 0 startvalue, 0.1 endvalue from dual union all
  3  select 1, 2, 0, 0.2 from dual union all
  4  select 1, 3, 0, 0.3 from dual union all
  5  select 2, 1, 0, 1 from dual union all
  6  select 2, 2, 0, 2 from dual union all
  7  select 2, 3, 0, 3 from dual
  8  /
6 rijen zijn aangemaakt.
SQL> merge into mytable t1
  2  using ( select rowid rid
  3               , lag(x,1,0) over (partition by id order by ordering) a
  4               , x b
  5            from ( select id
  6                        , ordering
  7                        , sum(endvalue-startvalue) over (partition by id order by ordering) x
  8                     from mytable
  9                 )
10        ) t2
11     on ( t1.rowid = t2.rid )
12   when matched then
13        update set sum_a = t2.a, sum_b = t2.b
14   when not matched then
15        insert values (null,null,null,null,null,null)
16  /
6 rijen zijn samengevoegd.
SQL> select * from mytable
  2  /
        ID   ORDERING STARTVALUE   ENDVALUE      SUM_A      SUM_B
         1          1          0         ,1          0         ,1
         1          2          0         ,2         ,1         ,3
         1          3          0         ,3         ,3         ,6
         2          1          0          1          0          1
         2          2          0          2          1          3
         2          3          0          3          3          6
6 rijen zijn geselecteerd.Regards,
Rob.