Help with printing a tic tac toe board (using a loop to print)

Question

hey im making the smiple game tic tac toe and im tryin to print out the board after each turn. I have a 2d array called char which is a 3 by 3 array and i dont know how i would make a for loop to print out the x's and o's in their right spot and still have the board look like a normal tic tac toe board. When the board is printing the x's and o's are already in the 2d char array board.So basically what i want to happen is after player 1's turn is up wherever he put the x replace the number on the board with an x and keep the rest the same and whenever player 2's turn is up wherever he put the o replace the number on the board with an o and keep the rest the same. Any help would be awesome thanks alot.
Here is the code to the program (i know i use if statements to much its a bad habit of mine)
import java.util.*;
public class Tictactoe
    private char board [] [] = new board [3] [3];
    private int X;
    private int O;
    private Scanner p1choice;
    private Scanner p2choice;
    Scanner input = new Scanner(System.in);
    public Tictactoe()
        p1choice = new Scanner(System.in);
        p2choice = new Scanner(System.in);
        play();
    public void play()
        printoriginalboard();
    public void printoriginalboard()
        System.out.println("    |    |    ");  
        System.out.println("  3 |  2 |  1 ");
        System.out.println("____|____|____");
        System.out.println("    |    |    ");
        System.out.println("  6 |  5 |  4 ");
        System.out.println("    |    |    ");
        System.out.println("____|____|____");
        System.out.println("    |    |    ");
        System.out.println("  9 |  8 |  7 ");
        System.out.println("    |    |    ");
        System.out.println("This is the classic game of tictactoe simply pick a number 1 through 9 to place an x or an o in that area.");
        player1turn();
    public void player1turn()
        System.out.println("Player 1 pick an area to place an X");
        int p1choice= p1choice.nextInt();
        if(p1choice == 1 && p2choice == 1 || p1choice == 1){
            System.out.println("This spot has already been taken");
            else
            board[0][2] = 'x';
        pintboard();
        if(p1choice == 2 && p2choice == 2 || p1choice == 2){
        System.out.println("This spot has already been taken");
        else
            board[1][2] = 'x';
        pintboard();
        if(p1choice == 3 && p2choice == 3 || p1choice == 3){
        System.out.println("This spot has already been taken");
        else
            board[2][2] = 'x';
        pintboard();
        if(p1choice == 4 && p2choice == 4 || p1choice == 4){
        System.out.println("This spot has already been taken");
            board[0][1] = 'x';
        pintboard();
        if(p1choice == 5 && p2choice == 5 || p1choice == 5){
        System.out.println("This spot has already been taken");
        else
            board[1][1] = 'x';
        pintboard();
        if(p1choice == 6 && p2choice == 6 || p1choice == 6){
        System.out.println("This spot has already been taken");
        else
            board[2][1] = 'x';
        pintboard();
        if(p1choice == 7 && p2choice == 7 || p1choice == 7){
        System.out.println("This spot has already been taken");
        else
            board[0][0] = 'x';
        pintboard();
        if(p1choice ==8 && p2choice == 8 || p1choice == 8){
        System.out.println("This spot has already been taken");
        else
            board[1][0] = 'x';
        pintboard();
        if(p1choice == 9 && p2choice == 9 || p1choice == 9){
        System.out.println("This spot has already been taken");
        else
            board[2][0] = 'x';
        pintboard();
    public void p2turn()
        System.out.println("Pick an area to place an O");
        int p2choice = p2choice.nextInt();
        if(p2choice == 1 && p1choice == 1 || p2choice == 1){
        System.out.println("This spot has already been taken");
        else
            board[0][2] = 'o';
        pintboard();
        if(p2choice == 2 && p1choice == 2 || p2choice == 2){
        System.out.println("This spot has already been taken");
        else
            board[1][2] = 'o';
        pintboard();
        if(p2choice == 3 && p1choice == 3 || p2choice == 3){
        System.out.println("This spot has already been taken");
        else
            board[2][2] = 'o';
        pintboard();
        if(p2choice == 4 && p1choice == 4 || p2choice == 4){
        System.out.println("This spot has already been taken");
        else
            board[0][1] = 'o';
        pintboard();
        if(p2choice == 5 && p1choice == 5 || p2choice == 5){
        System.out.println("This spot has already been taken");
        else
            board[1][1] = 'o';
        pintboard();
        if(p2choice == 6 && p1choice == 6 || p2choice == 6){
        System.out.println("This spot has already been taken");
        else
            board[2][1] = 'o';
        pintboard();
        if(p2choice == 7 && p1choice == 7 || p2choice == 7){
        System.out.println("This spot has already been taken");
        else
            board[0][0] = 'o';
        pintboard();
        if(p2choice == 8 && p1choice == 8 || p2choice == 8){
        System.out.println("This spot has already been taken");
        else
            board[1][0] = 'o';
        pintboard();
        if(p2choice == 9 && p1choice == 9 || p2choice == 9){
        System.out.println("This spot has already been taken");
        else
            board[2][0] = 'o';
        pintboard();
    public void pintboard()
    {

Answer 1

Anyway the answer is that you are trying to create an array of char as there is no such thing as a board[3][3].
One of the best tools a programmer can do is learn how to break a big problem into little problems and work on each little problem in isolation, and then when finished combining the solutions together into the final program. You big mistake that I see here is trying to bite off more than you can chew: trying to create a whole functioning interactive program from just one class. Why give yourself a task that would be difficult even for an experienced java programmer? I suggest that you break this down into logical parts and try to solve the smaller problems before worrying about the whole. For instance, if I were doing something like this, I'd create a class called TTTBoard that encapsulated the tic tac toe board and nothing but the board. I'd think of it as an entity. When I wanted the current state of the board, I'd query the board via a method such as getCurrentState. I'd have methods for checking if position is free, for placing an x/o in a spot, for checking for win, etc... Then I'd create a user interface class where I'd give the users a choice and get their responses. I'd probably create a Game class to control it all. While this all seems daunting, you are trying to do essentially the same thing, but all in one huge class. My recommendation: study OOPs and learn to do it the smart way. Good luck.