How to display the all the days in the month

Question

Hi,
How to display with the single sql stmt all the dates in a
month.
Like :
1, 2, 3, 4....last_day month
or
1
2
3
4
...last_day of month

Answer 1

SQL> CREATE OR REPLACE FUNCTION all_days(v_date DATE)
  2  RETURN VARCHAR2 AS
  3 
  4   v_last_day NUMBER := TO_CHAR(LAST_DAY(v_date), 'DD');
  5   v_all_days VARCHAR2(1000);
  6  
  7  BEGIN
  8 
  9     FOR i IN 1..v_last_day
10     LOOP
11     
12        v_all_days := v_all_days || ' ' || i;
13 
14        IF INSTR(v_all_days, v_last_day) > 0
15        THEN
16      RETURN v_all_days;
17        END IF;
18     END LOOP;
19  END;
20  /
Function created.
SQL> select all_days(sysdate)
  2  from dual
  3  /
ALL_DAYS(SYSDATE)
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24
25 26 27 28 29 30 31
SQL> select all_days('01-feb-2002')
   2  from dual
   3  /
ALL_DAYS('01-FEB-2002')
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24
25 26 27 28
SQL> select all_days('01-feb-2004') --Next Leap Year
   2  from dual
   3  /
ALL_DAYS('01-FEB-2004')
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24
25 26 27 28 29