How to find structural differences between two tables?
I want to find the difference in structure between objects in two 11g databases:
Here I want to identify:
tables/ Views with same columns, same datatype, precision and constraints
Identify if the same indexes and triggers are present.
I do not want to compare the data.
can someone give suggestions on this please?
my first resource for SQL Developer questions is (That) Jeff Smith: http://www.thatjeffsmith.com/archive/2012/09/sql-developer-database-diff-compare-objects-from-multiple-schemas/.
Similar Messages
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How to find the structural difference between two tables
Hi all,
How to find the structural difference between two tables .
Oracle Database 11g Enterprise Edition Release 11.1.0.7.0 - Production
PL/SQL Release 11.1.0.7.0 - Production
CORE 11.1.0.7.0 Production
TNS for 32-bit Windows: Version 11.1.0.7.0 - Production
NLSRTL Version 11.1.0.7.0 - Production
Thanks,
P Prakashyou could try something similar to this, for each table pair that you want to compare:
SELECT 'TABLE_A has these columns that are not in TABLE_B', DIFF.*
FROM (
SELECT COLUMN_NAME, DATA_TYPE, DATA_LENGTH
FROM all_tab_columns
WHERE table_name = 'TABLE_A'
MINUS
SELECT COLUMN_NAME, DATA_TYPE, DATA_LENGTH
FROM all_tab_columns
WHERE table_name = 'TABLE_B'
) DIFF
UNION
SELECT 'TABLE_B has these columns that are not in TABLE_A', DIFF.*
FROM (
SELECT COLUMN_NAME, DATA_TYPE, DATA_LENGTH
FROM all_tab_columns
WHERE table_name = 'TABLE_B'
MINUS
SELECT COLUMN_NAME, DATA_TYPE, DATA_LENGTH
FROM all_tab_columns
WHERE table_name = 'TABLE_A'
) DIFF;that's assuming, column_name, data_type and data_length are all you want to compare on. -
Need to find the Difference between two table
Hello ,
I have stucked in program as below scenario:-
I have two tables of huge data of same structure in a same schema.I need to find the difference exact values in tables.
By using MINUS we can find the difference between two table ,i need to find the what exact difference in the there values with colunm and value at that column.
Example TableA
Col1 col2 col3 col4 col5.... col50
10 ABC 2001 EE 444 TT
40 XYZ 3002 RR 445 TT3
80 DEF 6005 YY 446 YY8
TableB
Col1 col2 col3 col4 col5.... col50
10 ABC 2001 EE 444 TT
40 XYZ 3002 RR 445 TT3
81 DEF 6005 Yu 447 YY8
I need to the out put like this :-
The Diffence between two table is
TableA.COL1=80 TableB.Col1=81, Different
TableA.Col4=YY TableB.col4=Yu,Different
TableA.Col5=446TableB.col5=447,Different
Please suggest me to write the pl/sql program for the same
thanx in advance
KKThanx friends for all your efforts
I have a sample code for the same,this will compare the two tables for single row in each table .
what r the modification needed for the multiple rows of values in the two tables??
Please suggest!!
CREATE OR REPLACE PROCEDURE test_compare
IS
TYPE t_col
IS
TABLE OF VARCHAR2 (30)
INDEX BY PLS_INTEGER;
l_col t_col;
j NUMBER := 0;
l_sql VARCHAR2 (2000);
col1 VARCHAR2 (30);
col2 VARCHAR2 (30);
val1 NUMBER;
val2 NUMBER;
status VARCHAR2 (30);
CURSOR c1
IS
SELECT column_id, column_name
FROM all_tab_columns
WHERE table_name = 'TEST1';
BEGIN
FOR i IN c1
LOOP
j := j + 1;
l_col (j) := i.column_name;
END LOOP;
FOR k IN 1 .. j
LOOP
l_sql :=
'SELECT '
|| ''''
|| l_col (k)
|| ''''
|| ', '
|| 'TEST2.'
|| l_col (k)
|| ', '
|| ''''
|| l_col (k)
|| ''''
|| ', '
|| 'TEST1.'
|| l_col (k )
|| ', '
|| 'DECODE(TEST2.'
|| l_col (k)
|| ' -TEST1.'
|| l_col (k)
|| ', 0, ''NO CHANGE'', ''CHANGED'') FROM TEST2, TEST1';
EXECUTE IMMEDIATE l_sql INTO col1, val1,col2, val2, status;
IF status = 'CHANGED'
THEN
DBMS_OUTPUT.put_line( 'TEST2.'
|| col1
|| '='
|| val1
|| ', TEST1.'
|| col2
|| '='
|| val2
|| ', '
|| status);
END IF;
END LOOP;
EXCEPTION
WHEN OTHERS
THEN
DBMS_OUTPUT.put_line ('Error:- ' || SQLERRM);
END;
/ -
How to find the difference between two date?
Hi,
I currently writing a date comparision program. Below is the idea analogy,
Currently i need to find how many day differences between 30 July 2003 and 22 June 2004. How can i use java to code it?
Thanks.there doesn't seem to be a direct way but try this:int daysBetween = 0;
Calendar c = new GregorianCalendar(2004, Calendar.JULY, 30);
Calendar d = new GregorianCalendar(2003, Calendar.JUNE, 22);
while (c.get(Calendar.YEAR) != d.get(Calendar.YEAR)) {
daysBetween += 360;
d.add(Calendar.DAY_OF_YEAR, 360);
daysBetween += c.get(Calendar.DAY_OF_YEAR) - d.get(Calendar.DAY_OF_YEAR);This gives the correct result of 404 (= 8 days from June 22 to June 30 + 366 days between July 1 of 2003 and 2004 + 30 days from July 1 to July 30) -
How to find common fields between two tables
Hi friends,
Is there any way to find out common fields between tables and linking the tables based on common fields.
Thanks and Regards,
Chitty.Hi Chitty,
Try using joins it will give the fields which are only common to both the fields.
Here s an example,
SELECT mara~matnr
marc~werks
INTO TABLE t_material
FROM mara AS mara INNER JOIN marc AS marc
ON maramatnr = marcmatnr
WHERE mara~mtart = p_mtart.
Much Regards,
Amuktha. -
How to find the difference between two timestamp column
Dear All,
please Solve my issue,
I have Table name Record which has the following columns,
Empid in number column, dat in timestamp
which has the following values
Expand|Select|Wrap|Line Numbers
empid dat
====== ====
101 4/9/2012 9:48:54 AM
101 4/9/2012 9:36:28 AM
101 4/9/2012 6:16:28 PM
101 4/10/2012 9:33:48 AM
101 4/10/2012 12:36:28 PM
101 4/10/2012 8:36:12 PM
101 4/11/2012 9:36:28 AM
101 4/11/2012 4:36:22 PM
Here I need to display the following columns,
empid,min(dat) as start,max(dat) as end and difference(max(dat)-min(dat) for each day,
for eg,
Empid Strart end difference
101 4/9/2012 9:48:54 AM 4/9/2012 6:16:28 PM 8.28
like this.
Here 3 different days are exists so It should return 3 records with the above mentioned columns,
Please Help me to get this.
Thank you,
Regards,
Gurujothi
Edited by: Gurujothi on Apr 25, 2012 4:45 AM>
101 4/9/2012 9:48:54 AM 4/9/2012 6:16:28 PM 8.28
>
why 4/9/2012 9:48:54?
why not 4/9/2012 9:36:28 AM ?
SQL>
SQL> with t as
2 (select 101 empid, to_timestamp('4/9/2012 9:48:54 AM', 'dd/mm/yyyy hh:mi:ss AM') dat from dual union all
3 select 101, to_timestamp('4/9/2012 9:36:28 AM', 'dd/mm/yyyy hh:mi:ss AM') dat from dual union all
4 select 101, to_timestamp('4/9/2012 6:16:28 PM', 'dd/mm/yyyy hh:mi:ss PM') dat from dual union all
5 select 101, to_timestamp('4/10/2012 9:33:48 AM', 'dd/mm/yyyy hh:mi:ss AM') dat from dual union all
6 select 101, to_timestamp('4/10/2012 12:36:28 PM', 'dd/mm/yyyy hh:mi:ss PM') dat from dual union all
7 select 101, to_timestamp('4/10/2012 8:36:12 PM', 'dd/mm/yyyy hh:mi:ss PM') dat from dual union all
8 select 101, to_timestamp('4/11/2012 9:36:28 AM', 'dd/mm/yyyy hh:mi:ss AM') dat from dual union all
9 select 101, to_timestamp('4/11/2012 4:36:22 PM', 'dd/mm/yyyy hh:mi:ss PM') dat from dual
10 )
11 select empid, min(dat) as start_dat
12 , max(dat) as end_dat
13 , max(dat)-min(dat) diff
14 from t
15 group by empid, trunc(dat)
16 /
EMPID START_DAT END_DAT DIFF
101 04.09.12 09:36:28,000000000 04.09.12 18:16:28,000000000 +000000000 08:40:00
101 04.11.12 09:36:28,000000000 04.11.12 16:36:22,000000000 +000000000 06:59:54
101 04.10.12 09:33:48,000000000 04.10.12 20:36:12,000000000 +000000000 11:02:24
SQL> -
Find the difference between two columns in an ssrs matrix ? MSCRM
Hi All,
I am working in reporting part of our project (On-line MSCRM 2013) & in reporting services.
I am trying to create report using fetch xml based. Below is the snap what we required the result.
Kindly help me, how to get the difference in both column. (Its a matrix table where year is grouped).
We need difference between both year Like (Plan Revenue of 2013 & Plan Revenue of 2014 difference in Plan Revenue Diff section) and same for Actual
Revenue.
https://social.microsoft.com/Forums/en-US/054d5ca4-0d38-4dc6-84a8-88866cc228fe/find-the-difference-between-two-columns-in-an-ssrs-matrix-mscrm?forum=crmdevelopment
Thanks,
Mohammad ShariqueHi Bro,
I used parametrized option for year and done the report,Currently we are getting values in Difference column now i want to show
that value in percentage. How can we show the percentage based on that value. Means i want to show the Difference in Percentage.
Kindly help me i tried but getting some issue. Below i am mentioning the code and snap with result.
Below expression using to showing Plan Revenue in Percentage for year.
=
Sum(IIF(Fields!new_year.Value =Parameters!StartYear.Value,cdec(Fields!new_planrevenueValue.Value/1000), cdec(0)))
- Sum(IIF(Fields!new_year.Value =Parameters!EndYear.Value,cdec(Fields!new_planrevenueValue.Value/1000), cdec(0)))
/IIF(Sum(IIF(Fields!new_year.Value = Parameters!StartYear.Value,cdec(Fields!new_planrevenueValue.Value/1000), cdec(0)))>0,
(Sum(IIF(Fields!new_year.Value = Parameters!StartYear.Value,cdec(Fields!new_planrevenueValue.Value/1000), cdec(0))))
,1)
)*100))
Result issue is as below in snap with highlighted in red colour.
Kindly help me on this issue also :) -
How to find the difference between Project costs & Cost center costs?
Hi all,
Can you please explain me ? What is project Cost & Cost center cost and which are the tables having those fields of project cost & cost center Costs? And how to find the difference between their costs ? And please give me the functional Idea about it?
Thanking you all in Advance...
Regards,
ChandruHi,
goto table COSP:
1) object-no. beginning with 'KS' refer to cost-centre
example: 'KSKOKA4711'
with KS, KOKA = controlling area and 4711 = cost centre
2) OBJNR beginning with 'PR' refer to projects / WBS-element
example PR00001234
Message was edited by: Andreas Mann -
X6 = "1/5/15 5:16 AM" & NOW ....................difference by Only Time
not date
X6 date and Time will be changing, Its not Constant
Dim myDateTime As DateTime = X6
Dim myDate As String = myDateTime.ToString("dd/MM/yy")
Dim myTime As String = myDateTime.ToString("hh:mm tt")
Dim myDateTime1 As DateTime = Now
Dim myDate1 As String = myDateTime1.ToString("dd/MM/yy")
Dim myTime1 As String = myDateTime1.ToString("hh:mm tt")
Need to use this function to find the Difference between Two Time. due to 12:00 AM isuue
Function XLMod(a, b)
' This replicates the Excel MOD function
XLMod = a - b * Int(a / b)
End Function
Output Required
dim dd = XLMod(myTime - myTime1)
Problem is myTime & myTime1 is String Need to convert them into Time, Later use XLMOD Funtion.Induhar,
As an addendum to this, I thought I'd add this in also: If you have two valid DateTime objects you might consider using a class which I put together a few years ago
shown on a page of my website here.
To use it, just instantiate with two DateTime objects (order doesn't matter, it'll figure it out) and you'll then have access to the public properties. For this example, I'm just showing the .ToString method:
Option Strict On
Option Explicit On
Option Infer Off
Public Class Form1
Private Sub Form1_Load(ByVal sender As System.Object, _
ByVal e As System.EventArgs) _
Handles MyBase.Load
Dim date1 As DateTime = Now
Dim date2 As DateTime = #1/1/1970 2:35:00 PM#
Dim howOld As New Age(date1, date2)
MessageBox.Show(howOld.ToString, "Age")
Stop
End Sub
End Class
I hope that helps, if not now then maybe at some point in the future. :)
Still lost in code, just at a little higher level.
Thanx frank, can use this in Future.... -
Function Module to find the Difference between two times.
Hi All,
Wud you plz let me know the Function Module to find the Difference between two times.
Input Time1( Hours:Minutes) Time2 ( Hours:Minutes)
Need Output in Hours:Minutes only . ( No seconds Needed )
Ex :
Input :
06:00 to 18:00 Output : 12:00
and 20:00 to 06:00 Output: 10:00 with +ve sign only. No -ve sign.
Thanks,
N.L.Narayanacheck this .
data : p_timel like sy-uzeit,
p_timeh like sy-uzeit,
diff like sy-uzeit,
di(8) type c .
p_timel = '200000'.
p_timeh = '060000'.
diff = p_timeh - p_timel.
concatenate diff+0(2) ':' diff+2(2) into di.
write:/ di.
also check for this.
p_timel = '060000'.
p_timeh = '180000'.
see if this can be implemented in ur code .
or else u can try with Fm L_TO_TIME_DIFF passing startdate enddate starttime endtime with UOM as MIN
hope this helps regards,
vijay -
How to find the difference between 2 time values in Java
hi all,
i have 2 time values
String time1="6:20";
String time2="21:30"
How to find the difference between 2 times in Java?
pls help
thanx in advance....Calculating Java dates: Take the time to learn how to create and use dates
Working in Java time: Learn the basics of calculating elapsed time in Java
Formatting a Date Using a Custom Format
Parsing a Date Using a Custom Format -
How to find out difference between IAS Oracle Home patches and 10.1.2 Oracl
How to find out difference between IAS Oracle Home patches and 10.1.2 Oracle Home patches.
I have read me document but i could not able to understand.
Please help meuser10721329 wrote:
How to find out difference between IAS Oracle Home patches and 10.1.2 Oracle Home patches.
I have read me document but i could not able to understand.
Please help meWhat docoument you are referring to?
If you source the application env file APPS<CONTEXT_NAME>.env file under $APPL_TOP directory then this will set ORACLE_HOME to 10.1.2
If you source the application env file <CONTEXT_NAME>.env file under $INST_TOP/ora/10.1.3 directory then this will set ORACLE_HOME to 10.1.3
Environment Settings
http://docs.oracle.com/cd/E18727_01/doc.121/e12841/T120505T120509.htm#F_92659x3Ax20H1x20Head1x3Ax20Environmentx20Settings
Thanks,
Hussein -
How to do find the difference between two time stamps
Hi all,
i have a table with 2 columns called GMT time and Local time . so i need to find difference between these two time stamps.
i tried like this
select to_date(GMT_TIME,'yyyy-mm-dd hh24:hi:ss')-to_date(LOCAL_TIME,'yyyy-mm-dd hh24:hi:ss') from date_table
the result is coming as follows ..
0.291666666667
i did not under stand the out put.
In my table GMT_TIME= 2011-06-26 00:00:00 and LOCAL_TIME=2011-06-25 17:00:00 ..
please help me how to get exact hours between two dates ..
Thanks
SreedharHi Sreedhar,
Your output (0.2916666) has the unit day.
You should multiply with 24 to get the unit hour.
select ( to_date(GMT_TIME,'yyyy-mm-dd hh24:hi:ss')-to_date(LOCAL_TIME,'yyyy-mm-dd hh24:hi:ss') ) * 24 from date_table;Rgds,
Tycho -
How to find outthe difference between the two serivce patch of Netweaver04s
Hi,
We have installed NetWeaver04s with sp13 patch. We want to upgrade this to latest patch avaiable on sap market place. I could see sp22 is the latest patch. I know all the procedure to download the patch. But before downloading I have to find out the difference between the latest patch available i.e. SP22 and the current patch installed i.e. SP13.
Could anybody guide me how to see the difference between any two patches avaiable on the SAP market place?
Let me know if you need more information on this.
--ChandanHi
For single patch info, if you click the INFO link in window from where you download the patch. You will get the information related to that patch.
eg
SAPJEE05_0-10003469.SCA SP05 for SAP J2EE Engine 7.00 0 Info 53976 14.12.2005
Try out this, can help you (some navigation required)
http://service.sap.com/sp-stack
Select your Product:
Select Source and Target Release and Componenets. Click Next
Navigate under "Additional Information"
eg:
SAP NetWeaver 7.0 (2004s) Support Package Stacks
can be found on the SAP NetWeaver 7.0 (2004s) Support Package Stacks Info-Pages for each available Support Package Stack
In the next window; again navigate further: you can find like this
New functionality available with the relevant SP Stack is described in Section "Release Notes" as part of the SAP Library. Please refer to SAP Help Portal -> SAP NetWeaver 7.0 -> Release Notes. Each scenario folder contains the new functionality available for each SP Stack.
eg.
http://help.sap.com/saphelp_nw04s/helpdata/en/5b/8c3842bb58f83ae10000000a1550b0/frameset.htm
This would give you information of changes in different releases. -
Find the difference between two internal table
how can i see the difference between two interal tables?
The requirement is as follows
1. We have a transparent table, which stores the employee data with EMP ID as key.
2. We load the transp table data into a interal table (B).
3. We get data from legecy system as file and it gets loaded into another internal table (A) (this also has the same EMP ID key and this will have latest addition/update to those emplyees).
Now we need to seperate out these data into three interal table Inserted (I), Deleted (D) and Updated (U).
We want to do followign things
I = A - B
D = B - A
Both A and B will have around 40k records. Hence we are trying to avoid the looping.
Please suggest the best option for us.
Thank you in advance.
Raghavendra>
RAGHAV URAL wrote:
> how can i see the difference between two interal tables?
> The requirement is as follows
>
> 1. We have a transparent table, which stores the employee data with EMP ID as key.
> 2. We load the transp table data into a interal table (B).
> 3. We get data from legecy system as file and it gets loaded into another internal table (A) (this also has the same EMP ID key and this will have latest addition/update to those emplyees).
>
> Now we need to seperate out these data into three interal table Inserted (I), Deleted (D) and Updated (U).
>
> We want to do followign things
> I = A - B
> D = B - A
>
> Both A and B will have around 40k records. Hence we are trying to avoid the looping.
>
> Please suggest the best option for us.
>
> Thank you in advance.
> Raghavendra
Hi Raghavendra,
Currently as of my knowledge, these operations are only possible through LOOPs. But LOOPign can be really fast here if you properly utilize the SORTING, READ with BINARY SEARCH and FIELD-SYMBOLS usage. I would say:-
Steps for Insert:-
SORT: A, B.
LOOP AT A ASSIGNING <WA_A>.
READ TABLE B WITH TABLE KEY key = <WA_A>-key BINARY SEARCH.
IF SY-SUBRC NE 0.
APPEND <WA_A> TO I.
ENDIF.
ENDLOOP.
Steps for Delete:-
SORT: A, B.
LOOP AT B ASSIGNING <WA_B>.
READ TABLE A WITH TABLE KEY key = <WA_B>-key BINARY SEARCH.
IF SY-SUBRC NE 0.
APPEND <WA_B> TO D.
ENDIF.
ENDLOOP.
Regards,
Ravi.
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