How to open url with two varible

Question

Hi everyone
Could you tell what wrong is in this line.          
String x="http://localhost/Test.php?memberID=ww&movieID=mm";
     Runtime.getRuntime().exec("cmd /c start iexplore "+x);
why does my Test.php always only get the first parameter?
Test.php only got member id is ww.
However movieID become undeclared.
Is '&' not working in java?
Thank you very one
Yang Bin
               

Answer 1

The browser is trying to parse the ampersand and following characters as an entity.
You could try this:
String path = "http://localhost/Test.php?";
String parameters = "memberID=ww&movieID=mm";
try {
    String request = path + java.net.URLEncoder.encode(parameters);
    Runtime.getRuntime().exec("cmd /c start iexplore " + request);
} catch (Exception e) {
}This may also require modification of your php.ini file (not sure).
Check here for more:
http://www.w3.org/TR/html4/appendix/notes.html#h-B.2.2
Hope this helps...