Int to hexadecimal

Hello
Can omeone show me how to convert a int to a hexadecimal value
thanks

http://java.sun.com/j2se/1.5.0/docs/api/java/lang/Integer.html#toHexString(int)

Similar Messages

How to switch a decimal integer to a hexadecimal int?

How to switch a decimal integer to a hexadecimal int? And contrary too?

If you are talking about String representations of integers, you can use the methods in java.lang.Integer:
For example, to convert from hexadecimal notation to an int-value you can use:
int x = Integer.parseInt("FF00E", 16); // Radix 16To convert an int value to to hexadecimal notation use:
String x = Integer.toHexString(1778);Søren

Need some explanition with hexadecimal int literals.

1st I googled and found nothing that can give me a satisfactory exampl/tutorial or explanation.
In my book it does not demonstrate how the output was achieved.
What I already know is that hexadecimal has 16 symbols from 0-9 + a-f.
Now how does one calculate the output in you head or paper in the following....
INPUT: 0xDEADCAFE
OUTPUT: -559035650
Thank you all in advance :)

Just like with the base-10 numbers that you're used to, but don't even think about what you're doing.
In base 10:
65 = (5 * 10^0) + (6 * 10^1) = 5 + 60 = 65
In base 8:
101 = (1 * 8^0) + (0 * 8^1) + (1 * 8^2) = 1 + 0 + 64 = 65.
Given that, and given that hex is base 16, and given that A=10, B=11, etc., it should be trivial, albeit tedious, to calculate the value for 0xCAFEBABE or 0xDEADBEEF, etc.
EDIT: Also, one must know about [twos complement|http://en.wikipedia.org/wiki/Twos_complement]
Edited by: jverd on Nov 10, 2008 11:30 AM

Assign hexadecimal value to an Integer variable preceding with zero

hi
i need to pass an hexadecimal value, preceding with zero (0).
like 0775
the above hexadecimal value should be assigned to an integer variable. While i am trying to assign it, the output could be truncate the preceding zero value. Is it possible to do my requirement without truncating the preceding zero.?
Edited by: sasi on Jul 23, 2012 7:09 PM

I agree on that, this can not be carried out the way you explained.
Either you store the hexadecimal value as a string, and convert it before arithmetic operations:
int number = Integer.parseInt("0775", 16);
Or you store it as an integer (no leading zero) and convert it to string as you display it:
int number = 0x0775;
System.out.printf("%1$04x", number);

Int to Hex Progam

Could someone help resolve this problem : I have created a program to change int to hex but it does not seem to woek ? What could be wrong ?
import java.lang.String;
import javax.swing.JOptionPane; // import class JOptionPane
public class KcHexConverter {
public static void main( String args[] )
     String value, s;// first string entered by user
     int ni=0;
          // read in first number from user as a string
          value = JOptionPane.showInputDialog( "Enter integer" );
// convert numbers from type String to type Hex
          ni = Integer.parseInt(value, 16);
          s = Integer.toHexString(ni);
// display the results
JOptionPane.showMessageDialog(null, "The equvalent in Hexadecimal is: " +s, "Results", JOptionPane.PLAIN_MESSAGE );
System.exit( 0 ); // terminate the program
}

Hi
you need to change:
ni = Integer.parseInt(value);//no need for a radix it is base 10
and you should catch a possible NumberFormatException (sb enters a letter).

Incompatible types - found java.lang.String but expected int

This is an extremely small simple program but i keep getting an "incompatible types - found java.lang.String but expected int" error and dont understand why. Im still pretty new to Java so it might just be something stupid im over looking...
import java.io.*;
import javax.swing.*;
import java.awt.event.*;
import java.awt.*;
public class Lab
public static void main(String []args)
int input = JOptionPane.showInputDialog("Input Decimal ");
String bin = Integer.toBinaryString(input);
String hex = Integer.toHexString(input);
System.out.println("Decimal= " + input + '\n' + "Binary= " + bin + '\n' + "Hexadecimal " + hex);
}

You should always post the full, exact error message.
Your error message probably says that the error occurred on something like line #10, the JOptionPane line. The error is telling you that the compiler found a String value, but an int value was expected.
If you go to the API docs for JOptionPane, it will tell you what value type is returned for showInputDialog(). The value type is String. But you are trying to assign that value to an int. You can't do that.
You will need to assign the showInputDialog() value to a String variable. Then use Integer.parseInt(the_string) to convert to an int value.

Converting hexadecimal value to double Hlep needed!!!

Is there a way that I can convert the following hexadecimal value into double:
String s = "16#1234#";
As converting this to long I am doing this
if (s.startsWith("16#") && s.endsWith("#"))
extractedValue = s.substring( 3, s.length()-1 );
longValue = Long.parseLong( extractedValue, 16 );
Is there any way I can do the same and change the above to double. If I use
doubleValue = Double.parseDouble(s);
gives me an error so I want to parse the above value and change it to double any tips of work arround.
Thnaks

double doubleValue;
doubleValue = Integer.valueOf(s.substring( 3, s.length()-1 ), 16).intValue();
this works because int is big enough to handle 4 hex digits (can handle 7 hex digits safely)
then the conversion "widens" to double

USB Output Buffers - int to Hexed Chars

Hi all
With regards sending data to a USB device I set up a char like so:
size_t bufferSize = 8;
char *buffer = malloc(bufferSize);
I can then populate my bytes in hex (which seems to be the normal way of doing it).
    buffer[0] = 0xFF;
    buffer[1] = 0xEA;
The two fold question is will I have any issues if i populate the char buffers with integers?
    int value = 256;
    buffer[0] = value;
or does it have to be in hex?
If it requires hex (or even if not cos it would be good to know). What the best way to convert and integer to a hexed char?
Cheers
Steve

It doesn't matter if you specify the value in hexadecimal, decimal, octal or binary (or any other numbering system for that matter).
A number has the same value no matter what base you use.

Parsing hexadecimal strings

im an fresher currently in a project on secure hash algorithm
my project is stopped due to certain reasons , further which i cannot proceed.
i woud be grateful to u if some one provides solution to my problem.
int a = (word[i] << 1) or (word[i] >> 32-n)
word is an array that consist of hexadecimal string .
the thing here is for instance , 0x2g46778, 2g46778
when u print(both, individually) using System.out.println yields different results.
the scenario is i have derived word array that consist only number without 0x extension ,
but result yielded is wrong as for the reason mentioned above.
but when i take an array that consist of 0x as string and concat it with every element of word array i get the full number (i.e 0x 2hg4kr7)
again the problem is parsing the hexadecimal string(with ox as extension)
Query:
please tell me whether their is any way for parsing hexadecimal string as ox is not recognized.
or
how to proceed with it such that my string get parsed.
thank u
sincerly
hari hara ganesh dharmarajan
india`

Could you post some sample input and desired output for your project?
What is an array of hex string?
Is it String[] with the contents of each string consisting of the char a-f and 0-9? Eg String[] xx = new String[] {"1234", abcd"};
What does "parsing a hex string" mean? Give an example please.

Converting string to int

I cannot convert this string to integer.
int tempI = Integer.parseInt("fdcedfbd", 16);
it returns a numberFormatException
but if I do this then there will be no problem.
int tempI = 0xfdcedfbd
Can anybody help me with this? Thank you.

It sounds like the real problem here is that someone is giving you an 8-byte unsigned value represented as a 16-character hexadecimal string, and they want you to convert that into the actual 8 bytes. Are they going to do bit manipulation on it or something?
If you successfully convert it into a long and they then try to do math with it, they'll run into the sign/overflow problems everyone else has been talking about. If they just want to look at the individual bits then it would make sense to do the conversion into a long.
You could do something like this:
private static final String highOrderDigits = "89abcdef";
public long hexToLong(String hex) {
    // Only process exactly 16-digit strings.
    if (hex.length() != 16) {
      throw new IllegalArgumentException("Expect 16-digit hex value");
    boolean overflow = false;
    // Check for most significant digit > 7, which would
    // cause problem for parseLong.
    int highOrderIndex = highOrderDigits.indexOf(hex.charAt(0));
    if (highOrderIndex > -1) {
      // Clear most-significant bit and set overflow flag.
      overflow = true;
      hex = "" + highOrderIndex + hex.substring(1);
    long result = Long.parseLong(hex, 16);
    if (overflow) {
      // Manually set most significant bit in result.
      result |= 0x8000000000000000L;
    return result;
}I more or less tested this and it looks to work.

Java UDF help: Hexadecimal to Chinese Unicode converison

Hi Experts,
can someone help me in a design solution to convert Hexadecimal Values to Chinese Characters while sending the data to receiver system.
I am not able to get any methods in Java to do the conversion.
Help is appreciated.
Regards,
Prakash.

Hi Grzegorz Glowacki,
I am sorry this is not working :(.
Sample input: 4E2D56FD     -->basically this hexavalues are chinese character representation.
Output for it: ?????????
+for verification:open Wordpad-->copy the hexcode >select 4chars at a time> hit <altx> and you will get corresponding conversion value.++
String result = new String();
try {
byte[] bytes = new byte[input.length()/4];
    for (int i = 0; i < input.length()/4; i++) {
      byte value = Integer.valueOf(input.substring(i*4,i*4+4), 16).byteValue();
      bytes<i> = new Byte( value );    *//Byte cannot be stored in byte*
    result = new String(bytes, "UTF-16");
catch (UnsupportedEncodingException e){}
return result;
Also this is PI7.0 system. please do help.
thanks in advance.
Regards,
Prakash.
Edited by: senthilprakash selvaraj on Feb 2, 2012 9:38 AM

SAMPLE:C,DECIMAL TO HEXADECIMAL OR REVERSE

제품 : PRECOMPILERS
작성날짜 : 2002-05-26
SAMPLE:C,DECIMAL TO HEXADECIMAL OR REVERSE
==========================================
PURPOSE
다음의 간단한 두 C Source code들은
16진수를 10진수로 10진수를 16진수로 바꾸는 방법의 예를 보이고 있습니다.
EXAMPLE
prompt$ vi hex2dec.c
#include <stdio.h>
int main(void) {
unsigned int num;
printf("Hexadecimal number ? ");
scanf("%x", &num);
printf("(%d)10\n", num);
return 0;
:wq
prompt$ vi dec2hex.c
#include <stdio.h>
int main(void) {
unsigned int num;
printf("Decimal number ? ");
scanf("%d", &num);
printf("(%X)16\n", num);
return 0;
:wq
prompt$ cc -o hex2dec hex2dec.c
prompt$ cc -o dec2hex dec2hex.c
prompt$ ./hex2dec
Hexadecimal number ? 7FFF
(32767)10
prompt$ ./dec2hex
Decimal number ? 32767
(7FFF)16
Reference Document
------------------

Try the SDK forum.

Printing hexadecimal/binary numbers

I'm trying to print the hexadecimal and binary representation of the following:
public static void main(String[] args) {
int t = 0x1;
t = t<<30;
System.out.println(0xt);
I tried to print the hexadecimal representation of t using the above, but it didn't work (I know t isn't a hex number, but I want the contents of variable t printed in hex). How can I accomplish this?
Thanks ahead.

Use the Integer class. It has methods for binary and hex:
Integer.toBinaryString(int i);
Integer.toHexString(int i);

Int to binary

I was wondering if there is a function for turning an integer into a binary number? Thanks ( tried looking it up but all that came up was binary search and some other odd topics...)
me

int i = 1023;
    // Parse and format to binary
    i = Integer.parseInt("1111111111", 2); // 1023
    String s = Integer.toString(i, 2);     // 1111111111
    // Parse and format to octal
    i = Integer.parseInt("1777", 8);       // 1023
    s = Integer.toString(i, 8);            // 1777
    // Parse and format to decimal
    i = Integer.parseInt("1023");          // 1023
    s = Integer.toString(i);               // 1023
    // Parse and format to hexadecimal
    i = Integer.parseInt("3ff", 16);       // 1023
    s = Integer.toString(i, 16);           // 3ff
    // Parse and format to arbitrary radix <= Character.MAX_RADIX
    int radix = 32;
    i = Integer.parseInt("vv", radix);     // 1023
    s = Integer.toString(i, radix);        // vv

Sending Chararray of hexadecimal

Hi everyone.
im trying to send a chararray of hexadecimal in a socket, but when i catch it on the server it's not the same chararray...
this is the array i am sending from the client:
char[] _envio = {0x00,0x4C,0x60,0x00,0x05,0x80,0xE3,0x08,0x00,0x20,0x20,0x61,0x01,0x80,0xC0,0x00,0x02,
                        0x95,0x00,0x00,0x01,0x05,0x82,0x12,0x34,0x01,0x23,0x00,0x01};and this is what i am getting on the server:
0 4C 60 05 3F E3 8 0 20 20 61 1 3F C0 02 3F 0 0 15 3F12 34 1 23 01
note that the problem is when the hexadecimal is 0x80, 0x95 and 0x82 it is always change by 3F...
can someone tell me why this is happening?
this is how i am sending the chararray
char[] _envio = {0x00,0x4C,0x60,0x00,0x05,0x80,0xE3,0x08,0x00,0x20,0x20,0x61,0x01,0x80,0xC0,0x00,0x02,
                        0x95,0x00,0x00,0x01,0x05,0x82,0x12,0x34,0x01,0x23,0x00,0x01};
        try
            _serversocket = new Socket(_ipserver, _portserver);
            _out = new PrintStream(_serversocket.getOutputStream());
            _in = new BufferedReader(new InputStreamReader(
                _serversocket.getInputStream()));
              _out.println(_envio);
        catch (UnknownHostException ex)
            ex.printStackTrace();
        }and this is how i am chatching it in the server
try
                _in = new BufferedReader(new InputStreamReader(
                        _clientsocket.getInputStream()));
                _out = new PrintStream(_clientsocket.getOutputStream());
                _in.read(_msj);
                System.out.print("Mensaje del cliente: ");
                for(int i = 0; i < _msj.length; i++)
                   System.out.print(Integer.toHexString((int)_msj).toUpperCase());
System.out.println();
catch (IOException ex)
ex.printStackTrace();

Instead of PrintStream and BufferedReader (with InputStreamReader) you should use [url http://java.sun.com/j2se/1.5.0/docs/api/java/io/DataOutputStream.html#writeChar(int)]DataOutputStream.writeChar() and [url http://java.sun.com/j2se/1.5.0/docs/api/java/io/DataInputStream.html#readChar()]DataInputStream.readChar() because there is no special conversion involved.// client:
_out = new DataOutputStream(_serversocket.getOutputStream());
for (int i = 0; i < _envio.length; i++)
    _out.writeChar(_envio);
// server:
in = new DataInputStream(clientsocket.getInputStream());
for (int i = 0; i < _msj.length; i++)
_msj[i] = _in.readChar();Regards

Int to hexadecimal

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