Looking for SQL 2005 Backwards Compatibility ((( 8.05.2309 )))

We need to find the install for SQL 2005 Backwards Compatibility 8.05.2309   64 bit.
Can someone help with locating the install for this?
Thanks in advance for your assistance
Ed

Ed, would SQL Server 2005 Backward Compatibility Components version 8.05.2312 work for you?
http://www.exactsoftware.com/docs/DocView.aspx?DocumentID=%7B21509a73-9043-47d8-854c-318a3a35b585%7D

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    Anyone can help me to install de SQL Server 2005 Backward Compatibility componentes in Windows 7 home, Intel Core Duo
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    Hi,
    We can see this feature pack was issued in Nov 2005 from the site, which may not be updated
    to add Windows Vista/7 to supported operating systems. However, I can download and install X64 (64-bit)
    Microsoft SQL Server 2005 Backward Compatibility Components on Windows 7 Enterprise 64-bit successfully.
    If you get any error while installing, please let me know.
    Thanks,
    Chunsong
    Please remember to mark the replies as answers if they help and unmark them if they provide no help.

  • Looking for SQL*Net for Windows 95

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    despite that I do not know the type of the Firewall , I was able to adjust Oracle with Microsoft ISA server as follows :
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  • Looking for SQL Solution to Very Unique Problem

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    Edited by: BluShadow on 21-Feb-2012 13:52
    Email address removed for your own benefit, unless of course you'd like spam bots to pick it up and send you lots of rubbish?

    Why do I keep three tables. Each sample that is evaluated is always screened by what I will call a "tech." Every so many cases the test must be repeated for quality control. If the findings of the initial testing or of a quality control test are found to contain abnormal results, then the test must also be repeated, this time looked at by a doctor. So I have what I refer to as the "main" table; the one that holds final data, which in my example I explained the two "flag" fields that indicate if the test was repeated. Every time a test is evaluated it is done by the same person, and the findings of an individual testing, or screening, are a set of test result codes. There is the "main" control table which I have called LR in my example. The reason I have the other three tables: one is used to store the test results of the initial screening (always done); one is used to hold the test results of a quality control case (may or may not be done); and one is used to hold the test results of an abnormal case that was screened by a doctor (may or may not be done). There is a separate table for each individual who may have done a screening.
    Let us consider the results of just one case. In the table LR we have something like this:
    | KEY | P_STATUS | Q_STATUS |
    | 100 | Y | Y |
    By default, for any entry in the LR table there is always a set of codes in the SCR table. We know a quality control was performed because QC_STATUS=Y, and we know it was screened by a doctor because P_STATUS=Y. So we would have three different sets of findings, each in one of the three tables:
    SCR TABLE: QC TABLE:
    | KEY | CODE | | KEY | CODE | | KEY | CODE |
    | 100 | 014 | | 100 | 13R | | 100 | 13R |
    | 100 | 13R | | 100 | 150 | | 100 | 170 |
    | 100 | 150 | | 100 | 170 | | 100 | 180 |
    | 100 | 160 | | 100 | 190 |
    The values in the three tables represent the findings of three different people who screened the test sample. Now suppose I combined all the data, I would suppose it would look something like this:
    | KEY | P_STATUS | Q_STATUS | KEY | CODE | KEY | CODE | KEY | CODE |
    | 100 | Y | Y | 100 | 014 | null | null | null | null |
    | 100 | Y | Y | 100 | 13R | 100 | 13R | 100 | 13R |
    | 100 | Y | Y | 100 | 150 | 100 | 150 | null | null |
    | 100 | Y | Y | 100 | 160 | null | null | null | null |
    | 100 | Y | Y | null | null | 100 | 170 | 100 | 170 |
    | 100 | Y | Y | null | null | null | null | 100 | 180 |
    | 100 | Y | Y | null | null | null | null | 100 | 190 |
    Since P_STATUS=Y I would want the result set returned to be {13R, 170, 180, 190}.
    But suppose P_STATUS=N and Q_STATUS=Y then I would want the result set to be {13R, 150, 170}
    And if P_STATUS=N and Q_STATUS=N then I would want {014, 13R, 150, 160}
    Of all of the sets of test results codes, only ONE is ever the final word (i.e. the right answer).
    So what I was trying to do is find a query that would give me what I want. And my apologies if there is a major design flaw. I always thought it was not that bad. But then I am no SQL guru either.
    To anyone who has read on further my most humble thanks. I really did not mean to waste anyone's time or be a pain in the ass.
    Thanks Again,
    -JC

  • Optimal Locations for SQL 2005 TempDB & ReportServerTempDB MDF & LDF Files

    Hello.  I have SQL Server 2005 SP4 installed on Windows Server 2003 R2 Standard SP2. 
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    http://blogs.msdn.com/b/cindygross/archive/2009/11/20/compilation-of-sql-server-tempdb-io-best-practices.aspx
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    Regards, Ashwin Menon My Blog - http:\\sqllearnings.com

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    Hi!
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      2  /
    Table created.
    SQL> CREATE TABLE dt_test_b(b_id number, b_name varchar2(1),b_desc varchar2(10))
      2  /
    Table created.
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      4     DECODE(c.ordering, 2, b.b_name) b_name_2,
      5     DECODE(c.ordering, 3, b.b_name) b_name_3
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      8     dt_test_b b,
      9     dt_test_c c
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    11     a.a_id = c.a_id
    12  AND
    13     b.b_id = c.b_id
    14  /
         A_ID B B B
          100 A
          100   B
          100     C
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      2     a.a_id,
      3     MAX(DECODE(c.ordering, 1, b.b_name)) b_name_1,
      4     MAX(DECODE(c.ordering, 2, b.b_name)) b_name_2,
      5     MAX(DECODE(c.ordering, 3, b.b_name)) b_name_3
      6  FROM
      7     dt_test_a a,
      8     dt_test_b b,
      9     dt_test_c c
    10  WHERE
    11     a.a_id = c.a_id
    12  AND
    13     b.b_id = c.b_id
    14  GROUP BY
    15     a.a_id
    16  /
         A_ID B B B
          100 A B C
    SQL>
    SQL>
    SQL> insert into dt_test_a values(200)
      2  /
    1 row created.
    SQL> insert into dt_test_b values(40, 'A','One')
      2  /
    1 row created.
    SQL> insert into dt_test_b values(50, 'B','Two')
      2  /
    1 row created.
    SQL> insert into dt_test_b values(60, 'C','Three')
      2  /
    1 row created.
    SQL> insert into dt_test_c values(4, 40, 200, 3)
      2  /
    1 row created.
    SQL> insert into dt_test_c values(5, 50, 200, 2)
      2  /
    1 row created.
    SQL> insert into dt_test_c values(6, 60, 200, 1)
      2  /
    1 row created.
    SQL>
    SQL> SELECT
      2     a.a_id,
      3     MAX(DECODE(c.ordering, 1, b.b_name)) b_name_1,
      4     MAX(DECODE(c.ordering, 2, b.b_name)) b_name_2,
      5     MAX(DECODE(c.ordering, 3, b.b_name)) b_name_3
      6  FROM
      7     dt_test_a a,
      8     dt_test_b b,
      9     dt_test_c c
    10  WHERE
    11     a.a_id = c.a_id
    12  AND
    13     b.b_id = c.b_id
    14  GROUP BY
    15     a.a_id
    16  /
         A_ID B B B
          100 A B C
          200 C B A

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