Need Array Help Here..

Question

public class number
public static void main(String[]args)
{int a,b,g;
double box[] = new double[1000];
System.out.println("Enter a number");
a=Console.readInt();
System.out.println("Enter a number");
b=Console.readInt();
System.out.println("Enter a number");
g=Console.readInt();
initbox(a,b,box);
System.out.println("Your answer is"+intx2zero(a,b,box[],g));
public static void initbox(int a, int b , double box[])
{int k;
k=a-1;
     while (k<b)
     {k=k+1;
     System.out.println("Enter next integer");
     box[k]=Console.readInt();
public static int intx2zero(int a, int b, double box[],int g)
{int k,l;
boolean found;
k=a;
l=1;
found=false;
{if (box[k] == g)
     found=true;
     System.out.println(":"+l);
     k=k+1;
     l=l+1;
     else
     k=k+1;
     l=l+1;
im trying to write a code that will look at an array of numbers and output the "index" of the number that matches g, so say if G is 5 it would scan the array for which numbers match 5 in the array and print out the number which they were entered.
Heres what I tried to do I know it's wrong, but I got the first program to initialize the array and let the user enter the numbers the second would check if g == k if it did the boolean function gets true Then it would print out the number it came in then from there add one to k and one to l . So that the function would check the next number, and l would go up on cause thats the index of the next number. Now I was thinking what if the if statement was false then we just would go up one and try that one it sounds solid to me but on we go eh? Any points to be made to dont hold back ..

Answer 1

eep!
Wow, that's some... interesting code you've written there. That compiles?
You seem to be lacking a basic grasp of block-structured coding. I suggest looking at some examples of other people's programs, particularly at the way they "format" their code -- the way they group instructions which logically go together, and the way they indent to make it more readable.
More toward answering your question, take a look at the for keyword. It lets you do something repeatedly (like examining numbers), and provides a handy way of counting the number of times you do it (so you can examine all the numbers in an array, then stop.) Here's an example:
for(int i = 0; i < 10; ++i) {
   // do something
}Notice there are three statements inside the parentheses. When this code runs, it starts of by executing the first statement. In this case, it sets i to 0. Then it checks if the second statement is true, and if it is, it executes all the commands inside the block (between the curly braces). In this case, 0 < 10 is true, so it would execute the commands. Then, it executes the third statement in the parenthesis. In this case, it increments i by one, so now i == 1.
It continues evaluating the second statement (i < 10), executing the commands if it is true, and executing the third statement. It repeats this process until the second statement is no longer true. In this case, it will happen when i reaches 10.
What makes this really useful is that you can use the value of i to do different things inside the command block. For example, this for loop will print out the numbers 0 through 9:
for(int i = 0; i < 10; ++i) {
   System.out.println("i == " + i);
}From here, it's a small step to using the size of your array of numbers as the limit (i < array.length) and checking the numbers inside the loop, using the value of i as the index into your array.
Another thing... you shouldn't name your variables "a", "b", "g", etc. This is a terrible habit I learned from programming in Apple BASIC back in grade school, and trust me, the sooner you break it the better. Name your variables something meaningful.
Good luck...
Krum