Need clarification on the concept of "reset logs"

Hi,
When the database is in Archive log mode and once crashed will be recovered using the below command :
SQL> startup nomount
SQL> Alter database recover automatic using backup controlfile until cancel;
Once the database is recovered, we give the below command:
SQL> recover cancel;
After the above steps, we have to perform below command which I am not able to understand.
SQL> alter database open reset logs;
I am not able to appreciate the purpose of resetting the logs...why not we allow the database to proceed with the log file sequence.
Any information on the "reset logs" concept would be helpful to me.
Thanks in advance
Vineela

hi vineela,
this is the portal content management forum. for your database question please use the database forums:
http://forums.oracle.com/forums/index.jsp?cat=18
thanks,
christian

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                       Pair C     75   +/- 10 meters N/A                Short/Crosstalk
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Does this example mean that there's a cable length issue in the line which is causing the device that it's connected to not to work properly?
Example 2:
CXXX2SW140#show cable-diagnostics tdr int g0/21
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                          Pair C     N/A                     Pair C           Normal
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Example 3:
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Interface Speed Local pair Pair length            Remote pair Pair status
Gi0/22   auto    Pair A       1    +/- 10 meters N/A               Open
                          Pair B     39   +/- 10 meters   N/A               Open
                          Pair C     72   +/- 10 meters   N/A               Open
                          Pair D     1    +/- 10 meters    N/A              Open
Does this example mean that there isn't a device connected on the other end? No pin-contact?
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S

I found this article here at supportforums that seemed like the best explanation I've read so far for TDR info.
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Insert into Flatfile Values
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Application Software
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Primarily hierarchy query serves to process tree-like structures which RDBMS simulates using through parent-child relation, often in a single table (see famoust
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In your case it could look like:
SQL> select pgroup, pclass from flatfile;
PGROUP                         PCLASS
Application Software           Database Software
Application Software           Database Software
Application Software           Spreadsheet Software
Monitor                        15"
Monitor                        15"
Monitor                        17"
Monitor                        19"
Processor                      AMD
Processor                      Intel
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3 connect by prior pclass = pgroup
4 /
DECODE(LEVEL,1,PCLASS,''||PCLASS MANUFACTURER
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Database Software              Oracle
Database Software              Microsoft
Spreadsheet Software           Microsoft
Monitor
15"                            Acer
15"                            Sony
17"                            Philips
19"                            Viewsonic
Processor
AMD                            AMD
Intel                          Intel
12 rows selected.The hierarchy syntax is described completely in the documentation including
LEVEL and PRIOR keywords.
As for the ordering question you can use siblings ordering:
SQL> select decode(level,1,pclass,' ' || pclass), Manufacturer from flatfile
2 start with pgroup is null
3 connect by prior pclass = pgroup
4 order siblings by 1 desc
5 /
DECODE(LEVEL,1,PCLASS,''||PCLASS MANUFACTURER
Processor
Intel                          Intel
AMD                            AMD
Monitor
19"                            Viewsonic
17"                            Philips
15"                            Acer
15"                            Sony
Application Software
Spreadsheet Software           Microsoft
Database Software              Oracle
Database Software              Microsoft
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Need clarification on the sar -u command details

I have few scripts scheduled to run at the same time in the cron job.
The scripts are to basically executed to capture the following:
1. vmstat 1 10
2. mpstat 1 10
3. iostat 1 10
4. prstat 1 10
5. sar -u 1 10
6. sar -r 1 10
I found that the first record captured has less %idle compared to the other 9 times as per the sample below. Can anyone tell me if this is normal or is there anything wrong? Could this be due to the fact that when we run all the above cron job together, the CPU utilization is affected for the first reading? Please help.
SunOS DCWEBFES03 5.9 Generic_118558-04 sun4u 09/08/2006
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23:00:01 7 14 0 79
23:00:02 0 0 0 100
23:00:03 0 2 0 98
23:00:04 0 1 0 99
23:00:05 0 1 0 99
23:00:06 0 1 0 99
23:00:07 0 1 0 99
23:00:08 0 1 0 99
23:00:09 1 0 0 99
23:00:10 0 1 0 99
Average 1 2 0 97
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SunOS DCWEBFES03 5.9 Generic_118558-04 sun4u 09/08/2006
23:10:00 %usr %sys %wio %idle
23:10:01 5 14 0 81
23:10:02 0 1 0 99
23:10:03 1 0 0 99
23:10:04 0 1 0 99
23:10:05 0 0 0 100
23:10:06 0 1 0 99
23:10:07 0 1 0 99
23:10:08 1 1 0 98
23:10:09 0 2 0 98
23:10:10 0 1 0 99
Average 1 2 0 97
Fri Sep 8 23:20:00 WIT 2006
SunOS DCWEBFES03 5.9 Generic_118558-04 sun4u 09/08/2006
23:20:00 %usr %sys %wio %idle
23:20:01 8 11 0 81
23:20:02 0 1 0 99
23:20:03 0 1 0 99
23:20:04 0 1 0 99
23:20:05 0 1 0 99
23:20:06 0 0 0 100
23:20:07 0 1 0 99
23:20:08 0 0 0 100
23:20:09 0 1 0 99
23:20:10 0 1 0 99
Average 1 2 0 97
Fri Sep 8 23:30:00 WIT 2006
SunOS DCWEBFES03 5.9 Generic_118558-04 sun4u 09/08/2006
23:30:00 %usr %sys %wio %idle
23:30:01 7 12 0 81
23:30:02 0 1 0 99
23:30:03 0 1 0 99
23:30:04 0 2 0 98
23:30:05 0 1 0 99
23:30:06 0 0 0 100
23:30:07 0 1 0 99
23:30:08 0 1 0 99
23:30:09 0 1 0 99
23:30:10 0 1 0 99
Average 1 2 0 97
Fri Sep 8 23:40:00 WIT 2006
SunOS DCWEBFES03 5.9 Generic_118558-04 sun4u 09/08/2006
23:40:01 %usr %sys %wio %idle
23:40:02 9 12 0 79
23:40:03 0 1 0 99
23:40:04 0 1 0 99
23:40:05 0 1 0 99
23:40:06 0 0 0 100
23:40:07 0 0 0 100
23:40:08 0 1 0 99
23:40:09 0 1 0 99
23:40:10 0 1 0 99
23:40:11 0 0 0 100
Average 1 2 0 97
Fri Sep 8 23:50:00 WIT 2006
SunOS DCWEBFES03 5.9 Generic_118558-04 sun4u 09/08/2006
23:50:00 %usr %sys %wio %idle
23:50:01 6 12 0 82
23:50:02 2 3 0 95
23:50:03 0 2 0 98
23:50:04 0 2 0 98
23:50:05 0 0 0 100
23:50:06 0 1 0 99
23:50:07 0 0 0 100
23:50:08 0 1 0 99
23:50:09 0 1 0 99
23:50:10 0 1 0 99
Average 1 2 0 97

Its normal. The reason being that the first output from each command will be a summary of the records from boot til the command was run. Whereas the lines that follows will show the different between the first run and the second run.
In case that doesn't make sence:
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23:00:02 0 0 0 100 <== average since first run
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23:00:04 0 1 0 99 ... etc ...
23:00:05 0 1 0 99
23:00:06 0 1 0 99
23:00:07 0 1 0 99
23:00:08 0 1 0 99
23:00:09 1 0 0 99
23:00:10 0 1 0 99
7/M.

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Need clarification on the concept of "reset logs"

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