Need to find all Bugs and QF created for 8.0.0.13

Question

Hi all,
I kneed to know how to find all bugs and possibly patches/QF created on top of 8.0.0.13 for bugs found in 8.0.0.13 after its release on Jan 2012. This is for my Customer that needs to know if they have to plan some QF in proactive way.
I can access to Internal Support Portal, so if there is any place where Support people can go I can access.
Thank you in advance
Chiara Scarafiotti
ACS TAM

Answer 1

Hi radhika,,
This the the way to go..just modify the col according to your table col names...
You can do a CONNECT BY query without a START WITH clause to link every node with each of its ancestors.
Getting the total is just a matter of GROUP BY.
SELECT emp_id, employee_name, manager_id
, CASE
          WHEN COUNT (*) = 1
          THEN 0
          ELSE COUNT (*)
     END               AS cnt0
,     COUNT (*)      AS cnt1
FROM employee
CONNECT BY emp_id     = PRIOR          manager_id
GROUP BY emp_id, employee_name, manager_id
ORDER BY emp_id;
output:
Output:
. EMP_ID EMPLOYEE_N MANAGER_ID CNT0 CNT1
1 Mark 0 5 5
2 John 1 3 3
3 Stella 1 0 1
4 Karen 2 0 1
5 Andrea 2 0 1
I made this a bottom-up query (going from each node to its ancestors) rather that a top_down query (node to descendants) because you can't GROUP BY CONNECT_BY_ROOT.
In your description you implied that each node would be counted among its own descendants, but in the sample output you had 0, not 1, as the count for all the leaves, that is, managers counted as their own descendants, but non-managers did not. The column called count0 in the query above does that; the column count1 counts each node as its own descendant, leaves included.
Regards
Onenessboy