Regexp substr to select the max number out an string

Question

Hi all,
I need a solution for a query.
I,ve a query to select the lowest number in a string.
select regexp_substr('9 - 10','\d+')
from dual;
9
So this is the query I need to select the min number in he string.
but now I need it to give me the highest nr in the string .
the output that I need =10
Can someone help me pleasse?
My regards

Answer 1

Caroline wrote:
select regexp_substr('9 - 10','\d+')
from dual;
9
So this is the query I need to select the min number in he string.Actually it only gives you the first number in the string, not the minimum number.
SQL> select regexp_substr('9 - 10','\d+')
  2  from dual;
R
9If your string is the other way around it will give you 10 instead of 9.
SQL> ed
Wrote file afiedt.buf
  1  select regexp_substr('10 - 9','\d+')
  2* from dual
SQL> /
RE
10You probably want something like...
SQL> ed
Wrote file afiedt.buf
  1  with t as (select '9 - 10' as txt from dual)
  2  -- end of sample data
  3  select min(num) as min_num, max(num) as max_num
  4  from (
  5        select to_number(trim(REGEXP_SUBSTR (txt, '[^-]+', 1, level))) as num
  6        from t
  7        connect by level <= length(regexp_replace(txt,'[^-]*'))+1
  8*      )
SQL> /
   MIN_NUM    MAX_NUM
         9         10
SQL> ed
Wrote file afiedt.buf
  1  with t as (select '10 - 9' as txt from dual)
  2  -- end of sample data
  3  select min(num) as min_num, max(num) as max_num
  4  from (
  5        select to_number(trim(REGEXP_SUBSTR (txt, '[^-]+', 1, level))) as num
  6        from t
  7        connect by level <= length(regexp_replace(txt,'[^-]*'))+1
  8*      )
SQL> /
   MIN_NUM    MAX_NUM
         9         10
SQL>