Service Requests Open 5 days?/Service Requests Open and Closed Today

Help!
How would I determine service requests open greater then 5 days, I use the # of Open SR's but cannot seem to get a date to work.
Also what is the best way to count the SR's open and closed on the same day?
Thanks in advance.

You need to include a TIMESTAMPDIFF function in your filter... something to the effect of
TIMESTAMPDIFF(SQL_TSI_DAY,"Service Request"."Create Date",CURRENT_DATE) > 5
Double check the column reference.
Mike L

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Hi All,
I am trying to calculate for how long a SR has been open in business days only.
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(CASE
/* Convert Sunday to the Business Day Of the Year */
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(CASE
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/* Convert Saturday to the Business Day Of the Year */
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/* Convert Mon-Fri to the Business Day Of the Year */
ELSE (DAYOFYEAR("Service Request"."Opened Date") -
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END)
+
/* Adjust for Year Change */
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Any ideea or hint would be highly appreciated.
Thank you.
Regards,
Dorin
Edited by: user805960 on 06.01.2010 07:07

Hi,
i used this formula to find out the days it calculates between 31/12/2009 and 01/01/2010, the result it gave was 106 days.
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Thanks
Neena
Edited by: NNK on Jan 11, 2010 3:16 PM

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hi
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(CASE
/* Convert Sunday to the Business Day Of the Year */
WHEN DAYOFWEEK("Service Request"."Closed Date and Time") = 1
THEN (DAYOFYEAR("Service Request"."Closed Date and Time") -
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/* Convert Saturday to the Business Day Of the Year */
WHEN DAYOFWEEK("Service Request"."Closed Date and Time") = 7
THEN (DAYOFYEAR("Service Request"."Closed Date and Time") -
WEEK("Service Request"."Closed Date and Time")) -
(WEEK("Service Request"."Closed Date and Time") - 1)
/* Convert Mon-Fri to the Business Day Of the Year */
ELSE (DAYOFYEAR("Service Request"."Closed Date and Time") -
WEEK("Service Request"."Closed Date and Time")) +
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(CASE
/* Convert Sunday to the Business Day Of the Year */
WHEN DAYOFWEEK("Service Request"."Opened Date") = 1
THEN (DAYOFYEAR("Service Request"."Opened Date") -
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/* Convert Saturday to the Business Day Of the Year */
WHEN DAYOFWEEK("Service Request"."Opened Date") = 7
THEN (DAYOFYEAR("Service Request"."Opened Date") -
WEEK("Service Request"."Opened Date")) -
(WEEK("Service Request"."Opened Date") - 1)
/* Convert Mon-Fri to the Business Day Of the Year */
ELSE (DAYOFYEAR("Service Request"."Opened Date") -
WEEK("Service Request"."Opened Date")) +
(2 - WEEK("Service Request"."Opened Date")) END) +
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(365 * (YEAR("Service Request"."Closed Date and Time") -
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http://help.sap.com/saphelp_nw04s/helpdata/en/43/58e1cdbed430d9e10000000a11466f/frameset.htm
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Service Requests Open 5 days?/Service Requests Open and Closed Today

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