Simple exception chaining problem

Question

The problem is 'throw new ClientException(e.getMessage());' the error message kept stating to be in try/catch but it's already in try bracklet. I tried placing the exception in other bracklet but it defeats the purpose of showing the exception in this specific bracklet. I'm not sure what's the solution of this, I got the two solutions in netbeans - make a new try/catch or extending the exception. I looked at the book, I don't see this class extending anything.
import java.sql.Connection;
import java.sql.SQLException;
public class ClientBO {
    private Connection con;
    /** Creates a new instance of ClientBO */
    public ClientBO() {
        con = TomcatDAOFactory.createConnection();
    public void addSheet(SheetsForm sheetsform) {
        Connection con = null;
        try {
            TomcatClientDAO tomcatclientdao = new TomcatClientDAO(con);
            tomcatclientdao.createTest(sheetsform);
            con.commit();
        } catch (Exception e) {
            try {
                if (con != null) {
                    con.rollback();
                    throw new ClientException(e.getMessage());
            } catch (SQLException sqle) {
                e.printStackTrace();
                throw new RuntimeException("error.unexpected");
        } finally {
            try {
                if (con != null) {
                    con.close();
            } catch (SQLException sqle) {
                sqle.printStackTrace();
                throw new RuntimeException("error.unexpected");
}

Answer 1

You declare this:
private Connection con;
and define it in this constructor.
public ClientBO()
Next you declare this:
Connection con = null;
every line below this statement uses this locally defined variable 'conn',
not the class variable 'conn' declared in 'private Connection con' (got that?). So from that point on , conn is null.
Also, see my example on:
http://forum.java.sun.com/thread.jspa?threadID=5193839&messageID=9769059#9769059