Why 1.3/0.0 is not infinite

Question

double x = 1.7 / 0.0;
i want to know the reason why 1.7/0.0 is not infinite

Answer 1

It is possible your milage may vary depending on your
processor and OS, possibly even your Java
implementation.Hopefully not, because the language specification says:
# If either operand is NaN, the result is NaN.
# If the result is not NaN, the sign of the result is positive if both operands have the same sign, negative if the operands have different signs.
# Division of an infinity by an infinity results in NaN.
# Division of an infinity by a finite value results in a signed infinity. The sign is determined by the rule stated above.
# Division of a finite value by an infinity results in a signed zero. The sign is determined by the rule stated above.
# Division of a zero by a zero results in NaN; division of zero by any other finite value results in a signed zero. The sign is determined by the rule stated above.
# Division of a nonzero finite value by a zero results in a signed infinity. The sign is determined by the rule stated above.
# In the remaining cases, where neither an infinity nor NaN is involved, the exact mathematical quotient is computed. A floating-point value set is then chosen:
* If the division expression is FP-strict (�15.4):
o If the type of the division expression is float, then the float value set must be chosen.
o If the type of the division expression is double, then the double value set must be chosen.
* If the division expression is not FP-strict:
o If the type of the division expression is float, then either the float value set or the float-extended-exponent value set may be chosen, at the whim of the implementation.
o If the type of the division expression is double, then either the double value set or the double-extended-exponent value set may be chosen, at the whim of the implementation.