Why ..we have to use this ? public static void ? please !
hi ...im ibrahim ..and im new here in java nd new in the forum too ...nd please i would like to know ...why
do we use the method
public static void main (String []args)
i mean why ..static nd why public ..why void ....why main ..nd why (string []args)
...why we use it ...always ....hopefully ..im looking for a very clear answer to this ...issue ..?
please help .......!
public - this is the visibility modifier (it means that the body method can be call by any outside method)
static - the method is a static instance of the class. Not sure what exactly it does though.
void - this is the return type. void means that the method returns nothing.
main - the name of the method. It can be anything.
"public static void main" - this is the main method where upon executing the Java program the Java Virtual Machine will try to locate this method within the specifies class to be executed. This is always the first one to run when executing a Java program. None of this word may be changed or the program cannot be run.
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How to call java with public static void main(String[] args) throws by jsp?
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import java.net.MalformedURLException;
import java.io.IOException;
import com.openwave.wappush.*;
public class spServiceInd
private final static String ppgAddress = "http://devgate2.openwave.com:9002/pap";
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// private final static String[] clientAddress = {"+639209063665/[email protected]"};
private final static String SvcIndURI = "http://devgate2.openwave.com/cgi-bin/mailbox.cgi";
private static void printResults(PushResponse pushResponse) throws WapPushException, MalformedURLException, IOException
System.out.println("hello cze, I'm inside printResult");
//Read the response to find out if the Push Submission succeded.
//1001 = "Accepted for processing"
if (pushResponse.getResultCode() == 1001)
try
String pushID = pushResponse.getPushID();
SimplePush sp = new SimplePush(new java.net.URL(ppgAddress), "SampleApp", "/sampleapp");
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StatusQueryResult queryResult = queryResponse.getResult(0);
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System.out.println("*** ERROR - WapPushException (" + exception.getMessage() + ")");
catch (MalformedURLException exception)
System.out.println("*** ERROR - MalformedURLException (" + exception.getMessage() + ")");
catch (IOException exception)
System.out.println("*** ERROR - IOException (" + exception.getMessage() + ")");
else
System.out.println("Message failed");
System.out.println(pushResponse.getResultCode());
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How can i pass the values to method public static void showBoard(boolean[][
I need x and y to pass to the method
public static void showBoard(boolean[][] board
i am very confused as to why its boolean,i know its an array but does that mean values ar true or false only?Thanks
import java.util.Random;
import java.util.Scanner;
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public static void main(String[] args)
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int row, col, isAlive;
Random picker = new Random();
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public static void showBoard(boolean[][] board)
int row, col;
System.out.println();
for(row=0; row < x; row++)
for(col=0; col<y; col++)
if (board[row][col])
System.out.print("X");
else
System.out.print(".");
System.out.println();
System.out.println();
//This method creates the next generation and returns the new population
public static boolean[][] newBoard(boolean[][] board)
int row;
int col;
int neighbors;
boolean[][] newBoard = new boolean[board.length][board[0].length];
makeDead(newBoard);
for(row = 1; row < board.length-1; row++)
for(col = 1; col < board[row].length-1; col++)
neighbors = countNeighbors(row, col, board);
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if (neighbors < 2)
newBoard[row][col]=false;
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else if (neighbors == 2)
newBoard[row][col]= board[row][col];
else
newBoard[row][col] = true;
return newBoard;
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public static int countNeighbors(int thisRow, int thisCol, boolean[][] board)
int count = 0;
int row, col;
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if (board[thisRow][thisCol])
count--;
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}this is what im workin with mabey you can point me in the right directionimport java.util.Random;
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* Your final version of the program should explain the game and its use
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//Rewrite this method to allow the user to populate the board by entering the
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public static void fillBoard(boolean[][] board)
int row, col, isAlive;
Random picker = new Random();
for(row = 4; row < 9; row++)
for(col = 4; col < 9; col++)
if (picker.nextInt(2) == 0)
board[row][col] = false;
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board[row][col] = true;
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int row, col;
System.out.println();
for(row=0; row < 10; row++)
for(col=0; col<10; col++)
if (board[row][col])
System.out.print("X");
else
System.out.print(".");
System.out.println();
System.out.println();
//This method creates the next generation and returns the new population
public static boolean[][] newBoard(boolean[][] board)
int row;
int col;
int neighbors;
boolean[][] newBoard = new boolean[board.length][board[0].length];
makeDead(newBoard);
for(row = 1; row < board.length-1; row++)
for(col = 1; col < board[row].length-1; col++)
neighbors = countNeighbors(row, col, board);
//make this work with one less if
if (neighbors < 2)
newBoard[row][col]=false;
else if (neighbors > 3)
newBoard[row][col] = false;
else if (neighbors == 2)
newBoard[row][col]= board[row][col];
else
newBoard[row][col] = true;
return newBoard;
//This method counts the number of neighbors surrounding a cell.
//It is given the current cell coordinates and the board
public static int countNeighbors(int thisRow, int thisCol, boolean[][] board)
int count = 0;
int row, col;
for (row = thisRow - 1; row < thisRow + 2; row++)
for(col = thisCol - 1; col < thisCol + 2; col++)
if (board[row][col])
count++;
if (board[thisRow][thisCol])
count--;
return count;
//This method makes each cell in a board "dead."
public static void makeDead(boolean[][] board)
int row, col;
for(row = 0; row < board.length; row++)
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I am everytime getting the following error
Sorry! We could not complete the transaction using this payment method. Please contact support.
I have put my 2 credit card information with Microsoft. I tried calling 2 times the customer support but it was a pathetic response. In a single call I talked to 4 customer support officers and everybody passed on the call to the next without resolving the
problem, and without telling the next officer what is my issue!! they just passed on the phone call to avoid me!!
It is really frustrating that neither Microsoft is provide a good support (it was hard for them to understand my issue, in fact one of the support guy did not even know spelling of Azure.. he/she was saying it assure!!! and One of the guy told me that I
cannot use credit card outside US and Canada. then why you call yourself global???
So Microsoft you have a few things to do as your homework.
1. Your support is pathetic, frustrating and requires better people out there who know about your products, so train them first!
2. You got my 2 credit cards information which I see at subscriptions for Windows Azure, please remove both of them if you cannot provide a good support and subscription.
3. Learn from other cloud providers, AWS will otherwise kill your business.
Regards
Kajal
Kajal SinhaHi Kajal,
Sincerely apologize for this inconvenience, for billing & account issue, usually we need to contact the support team by creating a support ticket at
http://www.windowsazure.com/en-us/support/contact/. Or if that doesn't work because you don't have an active subscription you will need to contact general customer support to have them create
a support ticket for you
http://support.microsoft.com/gp/customer-service-phone-numbers?wa=wsignin1.0).
If above support channels don't work, at your convenient, could you please send an email to me: dxu at microsoft.com with kindly providing your:
Name
Email address
Phone number
We will provide help via emails. Thank you.
Best Regards,
Ming Xu
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