XSLT Transformation and GUI_UPLOAD

Can I use the GUI_UPLOAD to upload a XML in ABAP?
The problem is that I have to use an internal table for the upload but for the transformation I need a string, and both together don't work.

Small roundtrip, if you want to work with GUI_UPLOAD
TYPES: BEGIN OF ls_stringline,
         zeile   TYPE  string,
       END OF ls_stringline.
DATA: lv_filename  TYPE  string.
DATA: lv_xml_content      TYPE           ls_stringline,
      lt_xml_content      TYPE TABLE OF  ls_stringline.
DATA: lv_string    TYPE  string.
  CALL METHOD cl_gui_frontend_services=>gui_upload
    EXPORTING
      filename                = lv_filename
      filetype                = 'ASC'
    CHANGING
      data_tab                = lt_xml_content
    EXCEPTIONS
      file_open_error         = 1
      file_read_error         = 2
      no_batch                = 3
      gui_refuse_filetransfer = 4
      invalid_type            = 5
      no_authority            = 6
      unknown_error           = 7
      bad_data_format         = 8
      header_not_allowed      = 9
      separator_not_allowed   = 10
      header_too_long         = 11
      unknown_dp_error        = 12
      access_denied           = 13
      dp_out_of_memory        = 14
      disk_full               = 15
      dp_timeout              = 16
      not_supported_by_gui    = 17
      error_no_gui            = 18
      OTHERS                  = 19
CLEAR: lv_string.
LOOP AT lt_xml_content
INTO lv_xml_content.
  CONCATENATE lv_string lv_xml_content-zeile
         INTO lv_string.
ENDLOOP.
Now you have the full XML-Content in a variable of type string
and can give that to the transformation
      CALL TRANSFORMATION ztest
      SOURCE XML lv_string
      RESULT xmlresult = ls_xmlresult

Similar Messages

  • Need help on xslt transformation

    Hi ,
    I am working on a xslt transformation and  I am finding it difficult to implement the transformation. The scenario is as below.
    Input format :-
    A
    B
    B
    B
    4
    5
    A
    B
    B
    A
    B
    B
    B
    Output format :-
    A
    B
    B
    B (since after A there were 3 B’s before the next A)
    A
    B
    B(since after A there were two B’s before the next A)
    A
    B
    B
    B
    I don't need type 4,5 records in the output xml,output should have repetition of (A followed by B’s(till the next occurrences of A)).
    if some one encountered a similar transformation kindly let me know.

    Hi,
    You can use "Call" and "Apply" template.
    1st thing to do:
    e.g.
    <xsl:template name="Check_Decimal">
        <xsl:param name="Xpath"/>
        <xsl:choose>
          <xsl:when test="($Xpath) and ($Xpath)!='4'">
            <xsl:value-of select="$Xpath"/>
          </xsl:when>
          <xsl:otherwise>
            <xsl:value-of select="' ' '"/>
          </xsl:otherwise>
        </xsl:choose>
      </xsl:template>
                <xml_Target_Element_1>
                  <xsl:call-template name="Check_Decimal">
                    <xsl:with-param name="Xpath"
                                    select="/x/y/z/xml_Target_Element_1"/>
                  </xsl:call-template>
                </xml_Target_Element_1>
    This means, it will display the value in xpath if value is not equal to 4. And if it is equal to 4, it displays nothing.
    2nd thing to do:
    Apply for-each to xpath till the String element reaches to "A".
    Regards,
    Richa

  • How to run the ASDoc XSLT transformation manually?

    Hello there,
    I am combining the XML (toplevel.xml and toplevel_classes.xml) output of several actionscript projects into
    a one central XML file. I do this by first running the asdoc tool on the separate projects with the keep-xml and
    skip-xsl switches set to true. I then run my own XSLT script that combines the toplevel XML files and
    toplevel_classes XML files into two main files.
    After that I'd like to run the actual HTML generation, as far as I know its not possible to run asdoc with certain
    switches that tell it to skip the XML generation and just perform the XSLT transform immediately for a specified
    toplevel.xml and toplevel_classes.xml.
    Therefore I guess I have to run the XSLT tranforms from the 'templates' directory myself.
    So, thus my question is, what is the exact order of XSLT transforms and for which files?
    i.e. do I call class-list.xsl with toplevel_classes.xml, etc?
    thanx a lot in advance,
    Roland

    Hey there,
    yes, I understood what you meant, but even just the physical copying of the files will take a fair amount of time that I prefer to avoid
    I'm getting down with ANT as we speak Its a load of trial and error, but I'll report back if I have things working.
    Cheers,
    Roland

  • Help on xslt transformation

    Hi,
    I am working on a xslt transformation and  I am finding it difficult to implement the transformation. The scenario is as below.
    Input format :-
    A
    B
    B
    B
    4
    5
    A
    B
    B
    A
    B
    B
    B
    Output format :-
    A
    B
    B
    B (since after A there were 3 B’s before the next A)
    A
    B
    B(since after A there were two B’s before the next A)
    A
    B
    B
    B
    So basically I am not interested in 4,5 type records the output should have repetition of (A followed by B’s(till the next occurance of A)).
    if some has done any similar kind of transformation ,kindly let me know

    the pusedo code I am thinking for the above transformation is as below
    for-each of A
         do mappings using A's elements values
         Flag=Run
         For-each of B
              if flag!=stop
                    do B's mapping using B's elements values
                    if  next node is A
                    Flag=Stop
    But I came to know that varaibles once initilaised cannot be changed or modified .Also in the above approach in the second iteration of A when I say for-each of B ,xslt will start again from the first occurrence of B in the whole file and not from the B which is following the second A's occurence
    i am wondering if can this can be achieved in xslt or shoud we consider using only java?

  • BI Admin Tool and XSLT transformation for XML data source - How it works ?

    Hello,
    There is a possibility to import data from XML data source using BI Admin Tool.
    In the import window we can point XSLT file. What is the purpose of that XSLT field?
    Why I am asking ?
    I thought it is smth like XSLT processor, but simply it doesnt work.
    What I did:
    - I pointed XML data source file
    - I pointed XSLT transformation file
    - Click OK, and still get the message that the XML file structure is not supported
    After that I transformed that XML file with some desktop XSLT processor using the same XSLT file, and I tried to connect that file directly using BI Admin tool.Then it works. So it means that the transformation is ok.
    So basically one question comes to my mind in that situation:
    What is the purpose of XSLT field in BI Admin Tool when it comes to XML data source ?
    (it doesnt look like XSLT processor)
    Greetings
    /Michal

    Hi Mariano
    Why you need to use XSLT for transforming XML file into ABAP table
    Code is a part of some ABAP report. Looks like it is reading a file from file system and updating table after transformation
    If you have requirement like you need to read XML file and then insert the data into a SAP table
    You can use
    File to RFC
    File to Proxy scenario using SAP PI.
    Please provide more inputs on requirement to help
    Thanks
    Gaurav

  • XSLT producing different results via debugger and xslt.Transform()

    I'm producing the body of an email via an xsl. I've been having a problem with the html nested inside a <table> tag not displaying correctly. With a bit of help from the good folks over at the asp.net forums, I've tracked the problem down to getting
    different results if I run the xsl via the debugger or via a compiled transform.
    When I debug the xsl it produces
          <table border="1" cellpadding="4" cellspacing="0" style="..." id="tmsEmailTable">
            <tr>
              <th width="50%" align="center"><b>Issue</b></th>
              <th width="50%" align="center"><b>Resolution</b></th>
            </tr>
            <tr>
              <td>Missing Acknowledgement date</td>
              <td><p> Test test</p></td>
            </tr>
            <tr>
              <td>Missing Agent and/or Seller signature</td>
        </table>
    And that's absolutely correct and displays perfectly if I save the result as an html file. But when I use xslt.Transform(..), where xslt is a compiled transform, it produces
    <table border="1" cellpadding="4" cellspacing="0" style="..." id="tmsEmailTable">
                <tr><th width="50%" align="center"><b>Issue</b></th><th width="50%" align="center"><b>Resolution</b></th></tr>
                <tr>
                    <td>
                        Missing Acknowledgement date
                    </td>
                    <td></td>
                </tr>
            </table>
        </p><p> Test test</p></td></tr><tr>
            <td>Missing Agent and/or Seller signature</td>
            <td>
        </table>
    And to make it even more interesting, that extra </table> tag and the misplaced table data only occur on the first table row, but the table rows are generated by an xsl:for-each.
    The relevant bit of the xsl is:
              <table border="1" cellpadding="4" cellspacing="0" style="..." id="tmsEmailTable">
                <tr>
                  <th width="50%" align="center">
                    <b>Issue</b>
                  </th>
                  <th width="50%" align="center">
                    <b>Resolution</b>
                  </th>
                </tr>
                <xsl:for-each select="emailbody/checklist/item">
                  <xsl:if test="string-length(select='issue')>0">
                    <tr>
                      <td>
                        <xsl:value-of select="issue" disable-output-escaping="yes" />
                      </td>
                      <td>
                        <xsl:value-of select="resolution" disable-output-escaping="yes" />
                      </td>
                    </tr>
                  </xsl:if>
                 </xsl:for-each>
              </table>
    The code that generates the compiled transform and the (incorrect) output is:
                Dim xslt As XslCompiledTransform = New XslCompiledTransform(True)
                'Dim xslt As XslTransform = New XslTransform
                xslt.Load(templatePath) 
                Dim objStream As Stream = New MemoryStream(UTF8Encoding.UTF8.GetBytes(xmlData))
                Dim strbldrXML As StringBuilder = New StringBuilder()
                Dim objXmlReader As XmlReader = XmlReader.Create(objStream)
                Dim objXmlWriter As XmlWriter = XmlWriter.Create(strbldrXML)
                xslt.Transform(objXmlReader, objXmlWriter)
    I've checked that templatePath is pointing to the right file, and the source file I'm debugging the xsl against was copied from the xmlData parameter, so I know the same stuff is getting fed into it.
    I've been chasing this for days, and I'm about ready to quit and go get a job at a fast food joint. I'm not wonderful with xsl in general, or xsl in .NET in particular. Somebody PLEASE tell me I'm doing something stupid....
    Rebecca M. Riordan

    Thanks for the replay, Fred, but that wasn't the problem.
    I still don't know what the problem was, but in putting together a sample for review, I cleaned up the code a little (I inherited this), and while it
    appears to be functionally identical, it's working now. Since we're scheduled to go live on Friday, I'm gonna just take the win ;)
    In the unlikely event that anybody's curious, the original, non-functional code, looked like this:
    Public Function createEmailBody(ByVal templateType As String, ByVal xmlData As String) As String
                Dim templatePath, emailBody As String
                templatePath = Me.templatePath & "\" & templateType & ".xsl"
                Dim xpd As New XPathDocument(New StringReader(xmlData))
                Dim xslt As XslCompiledTransform = New XslCompiledTransform(False)
                xslt.Load(templatePath)
                Dim objStream As Stream = New MemoryStream(UTF8Encoding.UTF8.GetBytes(xmlData))
                Dim strbldrXML As StringBuilder = New StringBuilder()
                Dim objXmlReader As XmlReader = XmlReader.Create(objStream)
                Dim objXmlWriter As XmlWriter = XmlWriter.Create(strbldrXML)
                xslt.Transform(objXmlReader, objXmlWriter)
                emailBody = strbldrXML.ToString()
                Return emailBody
    End Function
    In cleaning it up, I wrote this:
    Public Function createEmailBody(ByVal templateType As String, ByVal xmlData As String) As String
                Dim xslt As XslCompiledTransform = New XslCompiledTransform(False)
                Dim templatePath As String = Me.templatePath & templateType & ".xsl"
                xslt.Load(templatePath)
                Dim reader As XmlReader = XmlReader.Create(New MemoryStream(UTF8Encoding.UTF8.GetBytes(xmlData)))
                Dim outSB As StringBuilder = New StringBuilder()
                Dim writer As XmlWriter = XmlWriter.Create(outSB)
                xslt.Transform(reader, writer)
                Dim emailBody As String = outSB.ToString()
                Return emailBody
    End Function
    As I said, they look functionally identical to me, but obviously they're not, because the second one works....
    Rebecca M. Riordan

  • Error when applying a XSLT transformation: No valid XSLT pro

    Dear All,
    I am getting following error when opening the "General Supplier Data" from Pre-Select Supplier.
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    Kindly Help.
    Regards,
    Sagar

    Hi Masa,
    Thanks for reply. I have checked this note. As note suggests, S_DEVELOP auth object is assigned to the user. and it has value *.
    Do I need to check anything else?
    Regards,
    Sagar

  • Error when applying a XSLT transformation

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    Hello Andrey Kuryanov,
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    Please provide more details with more detailed steps and actual error messge.
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  • UTF-8 encoding in XSLT transformation

    Hello,
    I have a problem with a transformation of an ABAP structure into XML. I use the XSLT transformation for this.
    My XSLT starts like this:
    <xsl:transform xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
      <xsl:strip-space elements="*"/>
      <asx:abap xmlns:asx="http://www.sap.com/abapxml" version="1.0">
        <asx:values>
    I tried many settings I could find posted on the internet, but I did not find one that would allow encoding to UTF-8.
    It always encodes to iso-8859-1 which my interface partner cannot read.
    Does anyone know a way to force encoding to UTF-8?
    Adding a command like <xsl:output encoding="utf-8"/> did not help.
    Thanks a lot!
           J. Euler

    Hello!
    I think I just solved the problem taking a different approach.
    In a note here on SDN, a guy from SAP wrote, that the SAP XSLT processor is not able to code anything but the system's default to a string, BUT that it is able to code it to an xstring.
    All I did now is add the tag  
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      DATA: tempxstring TYPE xstring,
            temp_length TYPE i,
            conv      TYPE REF TO cl_abap_conv_in_ce.
      CLEAR tempxstring.
      TRY.
          CALL TRANSFORMATION
              zxxje_tst_xslt
            SOURCE omsregdatawebservice = wa_data
            RESULT XML tempxstring.
        CATCH cx_sy_conversion_base64.
        CATCH cx_sy_conv_illegal_date_time.
      ENDTRY.
      IF tempxstring IS NOT INITIAL.
        CLEAR: conv, temp_length, string_xml_result.
        conv = cl_abap_conv_in_ce=>create( input = tempxstring ).
        conv->read( IMPORTING data = string_xml_result len = temp_length ).
      ENDIF.
    Thanks anyways for all your help!
    regards,
          Johannes Euler

  • ABAP XSLT transformation - XML to deep structure/nested standard table

    Hi all,
    I was struggling with this topic recently and couldn't find a single working example or description of a possible solution. So now that I've sorted it out, I did a quick example to elustrate how it works. Here is the code with XML embeded in it and the XSLT follows:
    <HR>
    <PRE>
    *& Report  Z_XML2ABAP
    *& Author: Jayanta Roy
    *& Date: 03/02/2010
    REPORT  z_xml2abap.
    DATA input_xml TYPE string.
    TYPES: BEGIN OF t_address,
            house_no TYPE string,
            street_name TYPE string,
            city_name TYPE string,
            phone_no TYPE string,
          END OF t_address.
    TYPES: t_addresses TYPE STANDARD TABLE OF t_address with NON-UNIQUE KEY house_no.
    TYPES: BEGIN OF t_person,
            firstname TYPE string,
            surname TYPE string,
            addresses TYPE t_addresses,
          END OF t_person.
    input_xml = '&lt;Friends&gt;' &&
      '&lt;People&gt;' &&
        '&lt;FirstName&gt;Homer&lt;/FirstName&gt;' &&
        '&lt;Surname&gt;Simpson&lt;/Surname&gt;' &&
          '&lt;Address&gt;' &&
            '&lt;HouseNo&gt;123&lt;/HouseNo&gt;' &&
            '&lt;Street&gt;Evergreen Terrace&lt;/Street&gt;' &&
            '&lt;City&gt;Springfield&lt;/City&gt;' &&
            '&lt;PhoneNo&gt;011212321&lt;/PhoneNo&gt;' &&
          '&lt;/Address&gt;' &&
          '&lt;Address&gt;' &&
            '&lt;HouseNo&gt;7G&lt;/HouseNo&gt;' &&
            '&lt;Street&gt;Neuclear Power Plant&lt;/Street&gt;' &&
            '&lt;City&gt;Spring Field&lt;/City&gt;' &&
            '&lt;PhoneNo&gt;911&lt;/PhoneNo&gt;' &&
          '&lt;/Address&gt;' &&
      '&lt;/People&gt;' &&
      '&lt;People&gt;' &&
         '&lt;FirstName&gt;Bart&lt;/FirstName&gt;' &&
         '&lt;Surname&gt;Simpson&lt;/Surname&gt;' &&
           '&lt;Address&gt;' &&
             '&lt;HouseNo&gt;123x&lt;/HouseNo&gt;' &&
             '&lt;Street&gt;Evergreen Terracex&lt;/Street&gt;' &&
             '&lt;City&gt;Springfieldx&lt;/City&gt;' &&
             '&lt;PhoneNo&gt;011212321x&lt;/PhoneNo&gt;' &&
           '&lt;/Address&gt;' &&
       '&lt;/People&gt;' &&
    '&lt;/Friends&gt;' .
    DATA lt_person TYPE STANDARD TABLE OF t_person.
    TRY.
        CALL TRANSFORMATION xslt_person
        SOURCE XML input_xml
        RESULT  all_people = lt_person.
      CATCH cx_root.
        WRITE 'Problemo!'.
    ENDTRY.
    WRITE 'Now, debug the program to see the values read from the XML'.
    </PRE>
    <HR>
    and here is the XSLT Transformation program (xslt_person):
    <HR>
    <PRE>
    &lt;xsl:transform xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
                        xmlns:sap="http://www.sap.com/sapxsl" version="1.0"&gt;
      &lt;xsl:strip-space elements="*"/&gt;
      &lt;xsl:template match="/"&gt;
        &lt;asx:abap xmlns:asx="http://www.sap.com/abapxml" version="1.0"&gt;
          &lt;asx:values&gt;
            &lt;ALL_PEOPLE&gt;
              &lt;xsl:apply-templates select="//People"/&gt;
            &lt;/ALL_PEOPLE&gt;
          &lt;/asx:values&gt;
        &lt;/asx:abap&gt;
      &lt;/xsl:template&gt;
      &lt;xsl:template match="People"&gt;
        &lt;ALLMYFRIENDS&gt;  &lt;!This element name is not relevent... needed to just group the loop&gt;
          &lt;FIRSTNAME&gt;
            &lt;xsl:value-of select="FirstName"/&gt;
          &lt;/FIRSTNAME&gt;
          &lt;SURNAME&gt;
            &lt;xsl:value-of select="Surname"/&gt;
          &lt;/SURNAME&gt;
          &lt;ADDRESSES&gt;
            &lt;xsl:for-each select="Address"&gt;
              &lt;ADDRESS&gt; &lt;!This element name is not relevent... needed to just group the loop&gt;
                &lt;HOUSE_NO&gt;
                  &lt;xsl:value-of select="HouseNo"/&gt;
                &lt;/HOUSE_NO&gt;
                &lt;STREET_NAME&gt;
                  &lt;xsl:value-of select="Street"/&gt;
                &lt;/STREET_NAME&gt;
                &lt;CITY_NAME&gt;
                  &lt;xsl:value-of select="City"/&gt;
                &lt;/CITY_NAME&gt;
                &lt;PHONE_NO&gt;
                  &lt;xsl:value-of select="PhoneNo"/&gt;
                &lt;/PHONE_NO&gt;
              &lt;/ADDRESS&gt;
            &lt;/xsl:for-each&gt;
          &lt;/ADDRESSES&gt;
        &lt;/ALLMYFRIENDS&gt;
      &lt;/xsl:template&gt;
    &lt;/xsl:transform&gt;
    </PRE>
    <HR>
    HTH,
    Jayanta.

    thanks a LOT Jayanta..
    I was looking for an XSLT example for some time.. this one atleast got me started in the right direction..
    THANKS

  • XSLT transformation in XML to ABAP: special characters issue

    Hi,
    I am parsing well-formed XML file that has the following data (:
    <projects><project><name>Wallis &amp; Futuna</name></project></projects>
    I use XSLT transformation:
    <xsl:transform xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:sap="http://www.sap.com/sapxsl" version="1.0">
    <xsl:strip-space elements="*"/>
    <xsl:template match="projects">
        <asx:abap xmlns:asx="http://www.sap.com/abapxml" version="1.0">
            <PROJECTS>
              <xsl:for-each select="project">
                <PROJECT>
                  <NAME>
                    <xsl:value-of select="name"/>
                  </NAME>
                </PROJECT>
              </xsl:for-each>
            </PROJECTS>
          </asx:values>
        </asx:abap>
      </xsl:template>
    </xsl:transform>
    If I use the above example without &amp;amp; everything works fine, but the original XML fails with exception CX_XSLT_DESERIALIZATION_ERROR and message "Error during deserialization". Googling around did not give an answer.
    Any words of wisdom?
    Edited by: Alexei Isaev on Apr 26, 2011 5:04 AM
    Edited by: Alexei Isaev on Apr 26, 2011 5:05 AM

    Hi,
    Please visit the following link for reference.
    http://help.sap.com/abapdocu_70/en/ABAPCALL_TRANSFORMATION.htm
    Thanks & Regards,
    Harish

  • XSLT transformation for XML to ABAP internal table

    Hi, can anyone please tell me how it should be the xslt tranformation to conver this xml
    <Embargos_ARBA_DOC>
         <ns:Embargos_ARBA_MT
              xmlns:ns="un:swissmedical:sap:proxy:embargos_arba:file">
              <Embargos_ARBA_MT>
                   <FECHA>20081101</FECHA>
                   <CUIT>50000002124</CUIT>
                   <MONTO>0000013794090</MONTO>
                   <RAZON_SOCIAL>RAUL ARMANDO CUNQUEIRO S.A.C.I.</RAZON_SOCIAL>
              </Embargos_ARBA_MT>
              <Embargos_ARBA_MT>
                   <FECHA>20081101</FECHA>
                   <CUIT>55000001456</CUIT>
                   <MONTO>0000001144410</MONTO>
                   <RAZON_SOCIAL>PARODI ESTEBAN ARMANDO</RAZON_SOCIAL>
              </Embargos_ARBA_MT>
         </ns:Embargos_ARBA_MT>
    </Embargos_ARBA_DOC>
    to this abap Table....
      DATA: BEGIN OF i_embargos_arba_doc occurs 0,
              fecha TYPE d,
              cuit TYPE char11,
              monto TYPE char13,
              razon_social(120),
            END OF i_embargos_arba_mt.
    so i can transform it with this sentence
          CALL TRANSFORMATION ('embargos_transformation')
            SOURCE XML source
            RESULT Embargos_ARBA_DOC = embargos.
    pls i need help because i am unable to create this xslt transformation...
    I will give the highest rewards points to the one who can help me.
    thanks!
    mariano

    Hi Mariano
    Why you need to use XSLT for transforming XML file into ABAP table
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    If you have requirement like you need to read XML file and then insert the data into a SAP table
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  • Source of xslt mapping and XSD/ XMT target structures for standard Idocs

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  • XSLT transformation for deep structure .....

    Hello,
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    </xsl:template>
    <xsl:template match="S_TEXTS">
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    <xsl:copy-of select="node()"/>
    </xsl:element>
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    <xsl:template match="T_APPRAISER">
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    </xsl:element>
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    <xsl:template match="T_APPRAISEE">
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    <xsl:for-each select="HAP_S_PDF_APPRAISEE">
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    <xsl:template match="T_OTHERS">
    <xsl:element name="T_OTHERS">
    <xsl:for-each select="HAP_S_PDF_OTHERS">
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    </xsl:for-each>
    </xsl:element>
    </xsl:template>
    <xsl:template match="T_PART_APPRAISER">
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    <xsl:for-each select="HAP_S_PDF_PART_APPRAISERS">
    <xsl:element name="DATA">
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    </xsl:for-each>
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    </xsl:template>
    <xsl:template match="T_PART_APPRAISER">
    <xsl:element name="T_PART_APPRAISER">
    <xsl:for-each select="HAP_S_PDF_PART_APPRAISERS">
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    <xsl:copy-of select="child::node()"/>
    </xsl:element>
    </xsl:for-each>
    </xsl:element>
    </xsl:template>
    <xsl:template match="S_STATUS">
    <xsl:element name="S_STATUS">
    <xsl:copy-of select="node()"/>
    </xsl:element>
    </xsl:template>
    <xsl:template match="S_DATES">
    <xsl:element name="S_DATES">
    <xsl:copy-of select="node()"/>
    </xsl:element>
    </xsl:template>
    <xsl:template match="S_DISPLAY">
    <xsl:element name="S_DISPLAY">
    <xsl:copy-of select="node()"/>
    </xsl:element>
    </xsl:template>
    <xsl:template match="STAT_CHG_BUTTON">
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      <xsl:template match="OFFLINE_ID">
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      <xsl:template match="BSP_FLAG">
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      <xsl:template match="ROLE">
    </xsl:template>
      <xsl:template match="APPRAISAL_YEAR">
    </xsl:template>
    </xsl:transform>
    Regards,
    Shishir.P

    "XSLT transformation for a deep structure"
    which way abap to xml or xml to abap?
    you may want to check this thread
    Re: Problem converting XML back to structure using XSLT

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