I changed my apple id email because i deleted that email.. I also changed my icloud email.. not it will not let me access icloud it wants to use the old one
I had to change my email addy due to too many hackers.. it was my apple id and my icloud and my imessage log in as well as face book
I deleted it after i created a new one.. I made the new one my apple id and my icloud id and imessage
However imessage does not work right now and Icloud has me log in with the new one and then when i am in askes me for the password with my old log in greyed out.... I have tried my new pass word as well as my old one.. neither work
Try temporarily recreating the old ID by going to https://appleid.apple.com, click Manage my Apple ID and sign in with your current iCloud ID. Click edit next to the primary email account, change it back to your old email address and save the change. Then edit the name of the account to change it back to your old email address. Now try using your current password when you are prompted for the password for the old ID. If successful, you can go back to https://appleid.apple.com and change your primary email address and iCloud ID name back to the way it was.
Similar Messages
-
I just updated my Apple ID to a current email address, it worked on my laptop but my phone is still using the old one and neither password works. I can't download or use anything other than phone calls and texting on my phone now. Help!
go to settings
then to store
tap your id then click sign out
then sign back in and you should be fine -
I created a new ID for my Iphone, because the old ID was an email address I no longer have. Also, the phone wouldn't recognize the password I have always used. Now the problem is when I try to update my apps, it automatically wants to use the old ID. I've set the new ID for the phone, but it defaults to the old one when asking for a password to update apps.
That's because all apps are forever tied to the Apple ID used to obtain them, & can only be updated using that ID.
To use your new ID with these apps, you'll have to delete them, then repurchase. Or, contact iTunes support, explain the situation, & ask that they add these apps to the download queue of your new ID. -
I changed my appleID but iCloud is still using the old one and no place to change it. How do I get iCloud to update to the new ID?
You have to sign out completely and then sign back in.
On a Mac, System Preferences>iCloud and click 'Sign out'.
On an iOS device, Settings>iCloud and click 'Delete account' (this will not delete the account from the server).
Your synced data will disappear from your devices when you sign out, but reappear when you sign back in (give it time). -
Can someone pls help me?? Okay..I've been trying to fix this for DAYS now! When I sign in (under settings) w my new apple ID, then go to update or purchase something I cannot get the new apple ID to come up. It's still using the old one (which is disabled) ..please help!
Delete what? The ID's? They cannot be deleted - you just quit using it.
If you still have one old ID - that you have purchased content with - you are saying that the password no longer works with that ID? Did you try to reset the password for that ID?
Read this - instructions if the ID was disabled for entering the wrong password.
http://support.apple.com/kb/TS2446?viewlocale=en_US&locale=en_US
If it gets too involved - you can always contact support.
http://www.apple.com/support/appleid/
Just do not create another ID! -
After changing my Apple ID I do not seem to be able to recognize it as my proper ID. It does work properly for an iTunes login and password, but, it is not displayed that way on my device when I look at my iCloud settings and other "system level" settings.
How do I correct this to be confident that I can use a feature, such as "Find My iPhone" and know that the functions and contact info is correct?To change the iCloud ID on your device you have to go to Settings>iCloud, tap Delete Account, provide the password to turn off Find My iPhone when prompted, then sign back in with the ID you wish to use.
-
I changed my itunes username and password a while ago, but it still sometimes keeps popping up. I now want to erase my iphone, but i can't because it is asking me for my old password, which i can't remember. My old user name was an email address, however i no longer have the email address!! Help please community.
https://iforgot.apple.com/
iOS: Unable to update or restore - http://support.apple.com/kb/HT1808 - recovery mode (e.g., cannot connect to computer last used to sync device, iTunes still asks for a password) -
JSP:I changed a class but WHY IT WANTS TO USE THE PREVIOUS ONE? HELP!!!!!!!
I am using HTMLform+JSP+javabean for executing a query into the database end showing the retrieved values.
For Building the query end Executing the query SQLQueryBean.class was used and it worked;
For showing retrieved values SQLResultSetBean.class was used: but the error page displaied cannot instanciate sql.SQLResultSetBean
After having tried many stuff I changed SQLResultSetBean with SQLQueryResultsBean.java that pratically works in a similar manner but I received error related with SQLResultSetBean.class ...WHY MY CHANGES HAVE NOT BEEN UPDATED?
This Is the jsp file:
<%@ page language="java"
import="java.sql.*, java.io.*, java.util.*, java.lang.*"
errorPage="errorpage.jsp"
%>
<jsp:useBean id="query" scope="page" class="sql.SQLQueryBean" />
<jsp:setProperty name="query" property="*"/>
</jsp:useBean>
<%--I TRIED TO HIDE THIS CODE BUT IT WAS USELESS
<jsp:useBean id="results" scope="page" class="sql.SQLQueryResultsBean" />
<jsp:setProperty name="results" property="*"/>
</jsp:useBean>
--%>
<jsp:useBean id="oneRow" scope="page" class="sql.SQLRow" />
<jsp:setProperty name="oneRow" property="*"/>
</jsp:useBean>
<html>
<body bgcolor="white">
<%! Integer identifier;%>
<%! String general; %>
<%! String[] ingr; %>
<%! Vector column = new Vector(); %>
<%! Vector whereCols = new Vector(); %>
<%! String myQuery = null; %>
<%-- ***** ACTION 1: Searching pizza names by ingredients! **** --%>
<%
String action = request.getParameter("action1");
if(action.equals("Search pizza")){
%>
<%-- ***** SETTING Database, table and columns for SELECT clause **** --%>
<hr>
<font size = 5 color ="red">
<center>
DEBUG:<br>
</font>
<font size = 2 color ="blue">
database: <%query.setDatabase("testkatia");
out.println(query.getDatabase());%>
<br>
table: <%query.setTable("relation1");
out.println(query.getTable());
query.selectColumns("pizza_id");
query.isDistinct(true);
column = query.getColumns();
%>
<br>
selected column(s) is(are):
<ul>
<%
if (!column.isEmpty()) {
for (int i = 0; i < column.size(); i++) {
%>
<li>
<%
out.println (column.get(i));
} else out.println ("none selected");
%>
</ul>
</font>
<hr>
<%-- ***** SETTING columns value and oper. for the WHERE clause **** --%>
<%
ingr = request.getParameterValues("Checkbox1");
if(ingr!= null){
for(int i = 1; i <=ingr.length; i++){
if(i>1 && i<=ingr.length)
query.selectAnd_OrForWhere("or");
for(int j=1; j<=24; j++){
if(ingr[i-1].equals(("ing"+j))){
general = String.valueOf(j);
query.selectWhereParameters("pizzaing_id","=",general, "integer");
%>
<font size=5 color ="red">
DEBUG:
</font>
<font size = 2 color ="blue">
<%
if(query.checkWhereParameters()){
out.println("Where Clause is Ok");
%>
<br>
<%
whereCols=query.getColsForWhere();
out.println("Cols for Where; "+ whereCols.toString());
else {
throw new Exception("parameters in the where clause are wrong!n whereClause = "+ query.getWhereClause());
%>
</font>
<hr>
<font size = 5 color ="red">
<center>
DEBUG:<br>
</font>
<font size =2 color= "blue">
The built query is: <%myQuery = query.buildQuery();
out.println(myQuery);
%>
<%--
<%!Vector rows = new Vector();%>
<%
if(myQuery!=null){
results = myQuery.queryExe(sqlQuery);
if(results == null) out.print("<br>SQLQueryResultsBean obj is NULL!");
out.println("<br>---retrieved row num. is--- "+results.getRowNumber());
out.println("<br>---Number of columns is--- "+results.getColNumber());
rows = results.getRetrievedRows();
if(!rows.isEmpty()){
out.print("col.: ");
for(int k= 0; k<results.getColNumber(); k++)
out.print((String)results.getColNames().get(k)+" ");
out.println("<br>");
for(int i=0; i < results.getRowNumber(); i++){
oneRow = (sql.SQLRow)rows.get(i);
out.print("<br>row"+(i+1)+": ");
for(int j=0; j<oneRow.rowSize(); j++)
out.print((String)oneRow.getRowValue(j)+" ");
out.println("<br>");
%>
--%>
</body>
</html>
The error that I got is:
Error: 500
Location: /goreme/jspFiles/searchPizzaOrIngr.jsp
Internal Servlet Error:
javax.servlet.ServletException: sql/SQLResultSetBean
at org.apache.jasper.servlet.JspServlet.service(JspServlet.java)
at javax.servlet.http.HttpServlet.service(HttpServlet.java)
at org.apache.tomcat.core.ServletWrapper.doService(ServletWrapper.java)
at org.apache.tomcat.core.Handler.service(Handler.java)
at org.apache.tomcat.core.ServletWrapper.service(ServletWrapper.java)
at org.apache.tomcat.core.ContextManager.internalService(ContextManager.java)
at org.apache.tomcat.core.ContextManager.service(ContextManager.java)
at org.apache.tomcat.service.connector.Ajp12ConnectionHandler.processConnection(Ajp12ConnectionHandler.java)
at org.apache.tomcat.service.TcpWorkerThread.runIt(PoolTcpEndpoint.java)
at org.apache.tomcat.util.ThreadPool$ControlRunnable.run(ThreadPool.java)
at java.lang.Thread.run(Thread.java:498)
Root cause:
java.lang.NoClassDefFoundError: sql/SQLResultSetBean
at java.lang.Class.getMethods0(Native Method)
at java.lang.Class.getDeclaredMethods(Class.java:1071)
at java.beans.Introspector$1.run(Introspector.java:858)
at java.security.AccessController.doPrivileged(Native Method)
at java.beans.Introspector.getPublicDeclaredMethods(Introspector.java:856)
at java.beans.Introspector.getTargetEventInfo(Introspector.java:562)
at java.beans.Introspector.getBeanInfo(Introspector.java:300)
at java.beans.Introspector.getBeanInfo(Introspector.java:87)
at org.apache.jasper.runtime.JspRuntimeLibrary.introspecthelper(JspRuntimeLibrary.java)
at org.apache.jasper.runtime.JspRuntimeLibrary.introspect(JspRuntimeLibrary.java)
at jspFiles._0002fjspFiles_0002fsearchPizzaOrIngr_0002ejspsearchPizzaOrIngr_jsp_70._jspService(_0002fjspFiles_0002fsearchPizzaOrIngr_0002ejspsearchPizzaOrIngr_jsp_70.java:111)
at org.apache.jasper.runtime.HttpJspBase.service(HttpJspBase.java)
at javax.servlet.http.HttpServlet.service(HttpServlet.java)
at org.apache.jasper.servlet.JspServlet$JspCountedServlet.service(JspServlet.java)
at javax.servlet.http.HttpServlet.service(HttpServlet.java)
at org.apache.jasper.servlet.JspServlet$JspServletWrapper.service(JspServlet.java)
at org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java)
at org.apache.jasper.servlet.JspServlet.service(JspServlet.java)
at javax.servlet.http.HttpServlet.service(HttpServlet.java)
at org.apache.tomcat.core.ServletWrapper.doService(ServletWrapper.java)
at org.apache.tomcat.core.Handler.service(Handler.java)
at org.apache.tomcat.core.ServletWrapper.service(ServletWrapper.java)
at org.apache.tomcat.core.ContextManager.internalService(ContextManager.java)
at org.apache.tomcat.core.ContextManager.service(ContextManager.java)
at org.apache.tomcat.service.connector.Ajp12ConnectionHandler.processConnection(Ajp12ConnectionHandler.java)
at org.apache.tomcat.service.TcpWorkerThread.runIt(PoolTcpEndpoint.java)
at org.apache.tomcat.util.ThreadPool$ControlRunnable.run(ThreadPool.java)
at java.lang.Thread.run(Thread.java:498)
Does somebody know what happened and why it continues to search SQLResultSetBean.class?...I have also restarted tomcat!!!![b]
Please drop me some helps! It would be really nice!
katiaTHANKS A LOT!
I am going on like a snail but maybe before die I will see this project works!
Unfortunately now I have got the previous error: that said:
"Error Page
Received the exception:
javax.servlet.ServletException: Cannot create bean of class sql.SQLQueryResultsBean"
While If I remouve the usebean tag for sql.SQLQueryResultsBean it dislpaied:
DEBUG:
database: testkatia
table: relation1
selected column(s) is(are):pizza_id
DEBUG: Where Clause is Ok
Cols for Where; [pizzaing_id, pizzaing_id, pizzaing_id]
DEBUG:
The built query is: SELECT DISTINCT pizza_id FROM relation1 WHERE pizzaing_id = 1 or pizzaing_id = 2 or pizzaing_id = 3
The built where clause is: WHERE pizzaing_id = 1 or pizzaing_id = 2 or pizzaing_id = 3
So why Cannot create SQLQueryResultsBean ?
JSP
All the code is here:
<%@ page language="java"
import="java.sql.*, java.io.*, java.util.*, java.lang.*"
errorPage="errorpage.jsp"
%>
<jsp:useBean id="query" scope="page" class="sql.SQLQueryBean" />
<jsp:setProperty name="query" property="*"/>
</jsp:useBean>
<%--
<jsp:useBean id="results" scope="page" class="sql.SQLQueryResultsBean" />
<jsp:setProperty name="results" property="*"/>
</jsp:useBean>
--%>
<jsp:useBean id="oneRow" scope="page" class="sql.SQLRow" />
<jsp:setProperty name="oneRow" property="*"/>
</jsp:useBean>
<html>
<body bgcolor="white">
<%! Integer identifier;%>
<%! String general; %>
<%! String[] ingr; %>
<%! Vector column = new Vector(); %>
<%! Vector whereCols = new Vector(); %>
<%! String myQuery = null; %>
<%-- ***** ACTION 1: Searching pizza names by ingredients! **** --%>
<%
String action = request.getParameter("action1");
if(action.equals("Search pizza")){
%>
<%-- ***** SETTING Database, table and columns for SELECT clause **** --%>
<hr>
<font size = 5 color ="red">
<center>
DEBUG:<br>
</font>
<font size = 2 color ="blue">
database: <%query.setDatabase("testkatia");
out.println(query.getDatabase());%>
<br>
table: <%query.setTable("relation1");
out.println(query.getTable());
query.selectColumns("pizza_id");
query.isDistinct(true);
column = query.getColumns();
%>
<br>
selected column(s) is(are):
<ul>
<%
if (!column.isEmpty()) {
for (int i = 0; i < column.size(); i++) {
%>
<li>
<%
out.println (column.get(i));
} else out.println ("none selected");
%>
</ul>
</font>
<hr>
<%-- ***** SETTING columns value and oper. for the WHERE clause **** --%>
<%
ingr = request.getParameterValues("Checkbox1");
if(ingr!= null){
for(int i = 1; i <=ingr.length; i++){
if(i>1 && i<=ingr.length)
query.selectAnd_OrForWhere("or");
for(int j=1; j<=24; j++){
if(ingr[i-1].equals(("ing"+j))){
general = String.valueOf(j);
query.selectWhereParameters("pizzaing_id","=",general, "integer");
%>
<font size=5 color ="red">
DEBUG:
</font>
<font size = 2 color ="blue">
<%
if(query.checkWhereParameters()){
out.println("Where Clause is Ok");
%>
<br>
<%
whereCols=query.getColsForWhere();
out.println("Cols for Where; "+ whereCols.toString());
else {
throw new Exception("parameters in the where clause are wrong!n whereClause = "+ query.getWhereClause());
%>
</font>
<hr>
<font size = 5 color ="red">
<center>
DEBUG:<br>
</font>
<font size =2 color= "blue">
The built query is: <%myQuery = query.buildQuery();
out.println(myQuery);
%>
<br>
The built where clause is:
<%
out.println(query.getWhereClause());
%>
</font>
</center>
<hr>
<%
%>
<%--
<%!Vector rows = new Vector();%>
<%
if(myQuery!=null){
results = myQuery.queryExe(sqlQuery);
if(results == null) out.print("<br>SQLQueryResultsBean obj is NULL!");
out.println("<br>---retrieved row num. is--- "+results.getRowNumber());
out.println("<br>---Number of columns is--- "+results.getColNumber());
rows = results.getRetrievedRows();
if(!rows.isEmpty()){
out.print("col.: ");
for(int k= 0; k<results.getColNumber(); k++)
out.print((String)results.getColNames().get(k)+" ");
out.println("<br>");
for(int i=0; i < results.getRowNumber(); i++){
oneRow = (sql.SQLRow)rows.get(i);
out.print("<br>row"+(i+1)+": ");
for(int j=0; j<oneRow.rowSize(); j++)
out.print((String)oneRow.getRowValue(j)+" ");
out.println("<br>");
%>
--%>
</body>
</html>
SQLQueryResultsBean
package sql;
import java.sql.*;
import java.util.*;
public class SQLQueryResultsBean {
String _sqlQuery;
ResultSet resultSet;
int colNumber;
int rowNumber;
Vector colTypes = new Vector();
Vector colNames = new Vector();
Vector _retrievedRows = new Vector();
//Constructor IS IT THIS THE PROBLEM?
public SQLQueryResultsBean(ResultSet rs){
this.setResultSet(rs);
//Methods for setting and retrieving the ResultSet object
public void setResultSet(ResultSet rs){
resultSet = rs;
public ResultSet getResultSet(){
return resultSet;
//Methods for setting and retrieving the Number of the column
public void setColNumber(int n){
colNumber = n;
public int getColNumber(){
return colNumber;
//Methods for setting and retrieving a vector containing all the names of the selected columns
public void setColNames(Vector c){
colNames = c;
public Vector getColNames(){
return colNames;
//Methods for setting and retrieving a vector containing all the types of the selected columns
public void setColTypes(Vector t){
colTypes = t;
public Vector getColTypes(){
return colTypes;
//Methods for setting and retrieving the number of the selected rows
public void setRowNumber(int n){
rowNumber = n;
public int getRowNumber(){
return rowNumber;
//Methods for storing and retrieving the rows selected with the query;
public void setRetrievedRows(Vector retrievedRows){
_retrievedRows = retrievedRows;
public Vector getRetrievedRows(){
return _retrievedRows;
//-----STORING THE RESULTS IN CLASS VARIABLES-----
//-----TYPES, NAMES, NUMBERS OF THE COLUMNS OF A GENERIC ROW AND-----
//-----FOR STORING THE NUMBER OF THE RETRIEVED ROWS-----
//storing the results before to close the connection
public void storeValues() throws SQLException {
ResultSet rs = this.getResultSet();
Vector rows = new Vector();
String value;
this.setRowNumber(this.countRowNumber());//set number of rows
this.setParameters(); //set number, types and names of the columns
//We Move the cursor to the given row number in this ResultSet object.
for(int i = 0; i<this.getRowNumber(); i++){
rs.absolute(i+1);
SQLRow newRow = new SQLRow();
//Then we retrieve values end collect them in a vector
for (int j=0; j<this.getColNumber(); j++){
value =rs.getString(j+1);
newRow.buildRow(value);
rows.add(newRow.getRow());
this.setRetrievedRows(rows);
//Methods for automatically setting this parameters:
//columnNumber, colNames, coltypes.
//It is not public but used inside storeValues();
void setParameters(){
try{
ResultSetMetaData meta = this.getResultSet().getMetaData();
int totColumns = meta.getColumnCount();
this.setColNumber(totColumns);
Vector names = new Vector();
Vector types = new Vector();
for (int i=1; i<=totColumns; i++){
names.add(meta.getColumnName(i));
types.add(meta.getColumnTypeName(i));
this.setColNames(names);
this.setColTypes(types);
}catch(Exception e){e.printStackTrace();}
//Methods for counting the number of the selected rows.
//It is not public but used inside storeValue();
int countRowNumber(){
int count=0;
try{
ResultSet rs = this.getResultSet();
// Moving the cursor to the front of this
//ResultSet object, just before the first row.
rs.beforeFirst();
while(rs.next())
count++;
rs.beforeFirst(); //replacecing cursor before the first row
}catch(Exception e){e.printStackTrace();}
return count;
If you (or someone on this forum) have any ideas for that I will be really grateful!
katia -
I am wondering if one of the apps from the IPad Air is causing a problem with my old IPad. If it is, How do I correct the problem?
Hey Tina,
If it is not working after the restore, then you may find more information by using another one of Apple's support resources. Checkout the link below for further assistance.
Contact Apple Support
https://getsupport.apple.com/GetproductgroupList.action
Regards,
-Norm G. -
How do I download the music from iTunes onto an old iPhone 3gs without affecting my iPhone 5? I have reset the iPhone to factory settings and when I plug it in it wants to use the device name for my current iPhone 5 and I don't want to change anything on my current iPhone. iTunes won't let me change the device name for the 3gs. I just want to use the old iPhone like an touch.
Hi littlemansa,
If I am understanding you correctly, it sounds like you are returning to an old iPhone that has been erased and you would like to set it up as a new device without restoring from a backup which would affect the name of your iPhone, as well as the contents therein. I have an article for you that can help you set up your iPhone as a new device, and that information can be found below:
How to erase your iOS device and then set it up as a new device or restore it from backups - Apple Support
http://support.apple.com/en-us/HT4137
Basically, it seems like you may be stuck on a screen that is asking if you would like to restore your device from the backup that is filed under the name of your new iPhone, or if you would like to set up the device as a new device. I would suggest that you set it up as a new device to achieve your desired results.
Take care, and thanks for visiting the Apple Support Communities.
-Braden -
I am going to run tests that require an actuator to move using various types of arbitrary waveforms such as sine or square. The NI 7344 is hooked to the UMI that is going through a driver for a servo valve. The loop is analog and it is closed. I have played with some of the examples but can't get it to work. I have used the function generator VI to generate a signal but I think I am using the wrong input VI to the motion control board. When I use what I have it moves the servo and then stops. It doesn't continually generate the signal.
I would love to use the controls on the function generator vi to control frequency and amplitude ect. Any help or pointer would be helpful. Thank you in advance.Hello,
I'm not clear on exactly how you want to use the generated data but I'm assuming they will be used as your target points.
There's a built-in example for motion called 'One-Axis Contour Move.vi'. This example demonstrates how to provide your target points as 1-D array. All you need to do is to replace the input array with the output of the function generator. In order to have it run continuously, use a while loop. You can further program your application so that it'll change the waveform on the fly by monitoring the user interface but this might be little little tricky as you will need to reset the move and load the new generated points while keeping track of your current position.
I hope this helps. Let me know if you have further questions regarding this
application.
Best regards,
Yusuf C.
Applications Engineering
National Instruments -
I had my iTunes stored on my external drive which crashed, i want to use the content stored on my 1st gen apple tv,but it won't recognize my new itunes library.
I had my iTunes stored on my external drive which crashed, i want to use the content stored on my 1st gen apple tv,but it won't recognize my new itunes library.
-
I changed my apple ID email address, and now I can't access my iCloud because it was listed with the previous email address. What can I do?
If the old ID ("email address") is an earlier version of your current ID, go to https://appleid.apple.com, click Manage my Apple ID and sign in with your current iCloud ID. Click edit next to the primary email account, change it back to your old email address and save the change. Then edit the name of the account to change it back to your old email address. You can now use your current password to turn off Find My iDevice, even though it prompts you for the password for your old account ID. Then save any photo stream photos that you wish to keep to your camera roll. When finished go to Settings>iCloud, tap Delete Account and choose Delete from My iDevice when prompted (your iCloud data will still be in iCloud). Next, go back to https://appleid.apple.com and change your primary email address and iCloud ID name back to the way it was. Now you can go to Settings>iCloud and sign in with your current iCloud ID and password.
-
I changed my email because I deleted the other one and I also forgot my security answers so I send a reset to my new email but it's not working it's going to the old one how do I send it to my new email
You need to contact Apple. Click here, phone them, and ask for the Account Security team, or fill out and submit this form.
(91761) -
I had to change my user ID because I used my email at my old job and now the old one keeps popping up and I can't sync my phone or authorize my computer at work to sync my phone. I have a new user ID and PW that allows me into ITUNES but that old one won't go away. Any help? Thanks
Hi, you can't change which ID was used to purchase any app. However, you can edit your Apple ID, which may be a better option than using a new id.
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