Setting a fix file output size regardless of input file..How?

I need to make several short movies that do not exceed 50MB in size as that is the limit set by my hosting company. Microsoft's movie allowed you to do this and would adjust the quality to suit. But how in Imovie?

1. There is no reliable way of guessing the encoding of a file without that information. Thats why XML for example has very strict rules wrt. it's encoding (short form: use UTF-8 or UTF-16, if you use anything else, you'll have to specify it)
2. you might be able to make an educated guess if the possible range of encodings is limited, but it will probably never be 100% certain
3. The HTML file might have a header entry "<meta http-equiv..." that tells you about it's encoding. You could try to read the start of the file and see if you find that, then if you found it re-read the entire file.
regards

Similar Messages

Help setting up for spicific output sizes

This is probably a very basic issue but I need help. I am using Premier Pro CS4 and have a variety of digital media sizes ranging from from 320x240 to 720x480 and need to find the correct way to set things up so i can scale the different sources up or down to match my final out put size of 480X360. And the best way to get a specific sized scale.
Thank you!!!

Ok this is driving me crazy...I have tried setting up new sequences, new projects and everything I can imagine. I thought I found it when I discovered that setting the program monitor to 100% doesn't actually show you the whole frame...what was I thinking - errrrrr. I set it to 75% and saw that all my media was not going edge to edge as suggested by Stanley above. I re-scaled all the media and then went to the export window and on the output screen I saw the re-size box was checked and I had black edges again. When I turned it off it changed the output size to 436X360.
HELP!!!!!!!!!!!
Here is a link to the screen grabs - http://johnandtj.com/pics/
Picture 1 shows my desktop with the preview and program window at 75% and that I have the correct sequence selected at the top of the program monitor (sequences settings in Picture 2).
Picuure 2 shows my sequence settings and the frame size of 480X360
Picture 3 shows my export settings and preview on the source tab
Picture 4 shows my my export settings and preview on the output tab and the fact that it sees the video as too tall hence the re-size is checked and it shrinks the video and gives black left and right.
Picture 5 shows my my export settings and preview on the output tab and the video fits but the re-size is unchecked and so the size is 436x360. (How is this possible).
PLEASE HELP me figure out this insanity (or just loan me a gun :-)
I will be off line till late pacific time and will hope to fine a miracle answer to get me going on this late night session...
MANY, MANY THANKS!

Need Help-SOA 11g File Adapter unable to delete input file and its crashing

Hi All
Please find the details below:
1. We have created a simple SOA composite to Read file from an input directory, archive the file in an archive directory using Inbound File Adapter Read
and then use Outbound File Adapter Write to move the file to a output directory.
2. File Adapter needs to delete the file after successful read/retrieval.
3. We are using the "Use Trigger File" for invoking the file adapter. This is a new feature in SOA 11g
4. Also we are using the option of reading the file as an attachment as we are not doing any transformation in the composite
Issue Details_
1. When the trigger file is put in the input directory for the first time, the File Adapter reads the file, archives it and moves it to the output directory
2. However it does not delete the input file from the input directory and raises Fatal Exception mentioned below:
[*2011-01-12T16:55:48.639+05:30] [soa_server1] [WARNING] [] [oracle.soa.adapter] [tid: weblogic.work.j2ee.J2EEWorkManager$WorkWithListener@19c243d]*
[userId: <anonymous>] [ecid: 0000IptyLrL9_aY5TrL6ic1DBOS_000009,0] [APP: soa-infra] File Adapter FileAdapterTriggerFilePOC PostProcessor::
Delete failed, the operation will be retried for max of [0] times
[2011-01-12T16:55:48.639+05:30] [soa_server1] [WARNING] [] [oracle.soa.adapter] [tid: weblogic.work.j2ee.J2EEWorkManager$WorkWithListener@19c243d]
[userId: <anonymous>] [ecid: 0000IptyLrL9_aY5TrL6ic1DBOS_000009,0] [APP: soa-infra] File Adapter FileAdapterTriggerFilePOC [[
BINDING.JCA-11042
File deletion failed.
File deletion failed.
File : C:\Dibya\AttachmentTest\InputDir\TestFile3.txt could not be deleted.
Delete the file and restart server. Contact oracle support if error is not fixable.
If any one has faced similar issues, kindly provide pointers on how to resolve it.
Regards,
Dibya

Hi,
Using the file adapter, you can poll from multilple locations...
Keep the following property in your .jca file
<property name="DirectorySeparator" value="," />
While giving the path in File Adapter configuration, keep comma and give the next location....then the file will be picked up from the locations you gave....
Hope this helps...
Thanks,
N

DES output size bigger than input size

If I try the code below for passwords and data of each 8 bytes, I get encrypted data of 16 bytes. Why is this so? I thought with DES the number of output bits equals the number of input bits.
Thanks,
J�rgen
static String A="DES";
private static byte[] encode(Key k, byte[] data) throws Exception
Cipher c = Cipher.getInstance(A);
c.init(Cipher.ENCRYPT_MODE, k);
byte[] enc = c.doFinal(data);
return enc;
byte[] passBytes = password.getBytes();
Key k = new SecretKeySpec(passBytes, A);
byte[] input = data.getBytes();
byte[] enc = encode(k,input);

see code below.
with "DES/CBC/NoPadding":
java.security.InvalidKeyException: Illegal key size or default parameters
with "DES/EBC/NoPadding"
java.security.NoSuchAlgorithmException: Cannot find any provider supporting DES/EBC/NoPadding
public class DESTest
     static String A=
//     "DES/EBC/NoPadding";
     "DES/CBC/NoPadding";
//     "DES";
     private static byte[] encode(Key k, byte[] data) throws Exception
          Cipher c = Cipher.getInstance(A);
          c.init(Cipher.ENCRYPT_MODE, k);
          byte[] enc = c.doFinal(data);
          return enc;
     private static byte[] decode(Key k, byte[] data) throws Exception
          Cipher c = Cipher.getInstance(A);
          c.init(Cipher.DECRYPT_MODE, k);
          byte[] enc = c.doFinal(data);
          return enc;
     public static void main(String[] args) throws Exception
          byte[] pass = "password".getBytes();
          byte[] data = "datadata".getBytes();
          Key k = new SecretKeySpec(pass, A);
          byte[] enc = encode(k,data);
          byte[] dec = decode(k,enc);
          String s = new String(dec);
          System.out.println(s);
}

Can I get fixed length output after encryption using PBEwithMD5andDES?

Hi,
I am currently using "PBEWITHMD5ANDDES" algorithm to encrypt the string and later it is encoded using BASE64. I need to store the value in Database so I need output to be of fixed size. Currently output depends on the input string length. My input string can vary in length.
I cannot use Message digest for storing it database as I need to decode too.
Sonal

You can't possibly have a fixed encrypted output size regardless of the input size and be able to recover the original. Just think about it for a bit. This would enable infinite compression.
PBEWITHMD5ANDDES uses PKCS5 padding and so produces an output which is (n+8)/8 blocks of 8 bytes so 1,2,3 ... 7 become 8 bytes, 8,9,10 ... 15 become 16 bytes etc etc etc.

Maximum input payload size(for an XML file) supported by OSB

Hey Everyone,
I wanted to know, what is the maximum payload size that OSB can handle.
The requirement is to pass XML files as input to OSB and insert the data of the XML files in the oracle staging tables. The OSB will host all the .jca,wsdl, xml, xml schema and other files required to perform the operation.
The hurdle is to understand, what is the maximum XML file size limit, that OSB can allow to pass through without breaking.
I did some test runs and got the following output,
Size of the XML file: OSB successfully read a file of size, 3176kb but failed for a file of size 3922kb, so the OSB breakpoint occurs somewhere between 3-4 MB, as per the test runs.
Range of number of Lines of XML: 102995 to 126787, since OSB was able to consume a file with lines (102995) and size 3176kb but broke for a file with number of lines (126787) and size 3922kb.
Request to please share your views on the test runs regarding the OSB breakpoint and also kindly share the results, if the same test has been performed at your end.
Thank you very much.

Hey Everyone,
I wanted to know, what is the maximum payload size that OSB can handle.
The requirement is to pass XML files as input to OSB and insert the data of the XML files in the oracle staging tables. The OSB will host all the .jca,wsdl, xml, xml schema and other files required to perform the operation.
The hurdle is to understand, what is the maximum XML file size limit, that OSB can allow to pass through without breaking.
I did some test runs and got the following output,
Size of the XML file: OSB successfully read a file of size, 3176kb but failed for a file of size 3922kb, so the OSB breakpoint occurs somewhere between 3-4 MB, as per the test runs.
Range of number of Lines of XML: 102995 to 126787, since OSB was able to consume a file with lines (102995) and size 3176kb but broke for a file with number of lines (126787) and size 3922kb.
Request to please share your views on the test runs regarding the OSB breakpoint and also kindly share the results, if the same test has been performed at your end.
Thank you very much.

Multiple replacements from an input file with 1.4 Regex

hi,
i'm trying to make multiple replacments to a source file <source> using a second input file <patterns> to hold the regex's. the problem i'm having is that the output file only makes the last replacement listed in the input file. Example if the input file is
a#123
b#456
only b is changed to 456 and a remains.
the second debug i've got shows that all the replacements are in memory, but i'm not sure how to write them all to the file.
the syntax is Java MyPatternMatcher <source> <patterns>
import java.util.regex.*;
import java.io.*;
import java.util.*;
public class MyPatternResolver {
     private File patternFile;
     private File sourceFile;
     private Vector patterns = new Vector();
     public MyPatternResolver(String sourceFile, String patternFile) {
          this.sourceFile = new File(sourceFile);
          this.patternFile = new File(patternFile);
          loadPatterns();
          resolve();
     private void loadPatterns() {
          // read in each line if File
          FileReader fileReader = null;
          try {
               fileReader = new FileReader(patternFile);
          } catch(FileNotFoundException fnfe) {
               fnfe.printStackTrace();
          BufferedReader reader = new BufferedReader(fileReader);
          String s = null;
          String[] strArr = new String[2];
          try {
               while((s = reader.readLine()) != null) {
                    StringTokenizer tokenizer = new StringTokenizer(s, "#");
                    for (int i =0; i < 2; i++) {
                         strArr[i] = tokenizer.nextToken();
                         //Debugging Info
                         System.out.println("Token Value " + i + " = " + strArr);
                         //End Debugging Info
                    patterns.add(new PatternResolver(strArr[0], strArr[1], sourceFile));
          } catch(IOException ioe) {
                    ioe.printStackTrace();
     private void resolve() {
          Iterator iterator = patterns.iterator();
          while(iterator.hasNext()) {
               PatternResolver pr = (PatternResolver) iterator.next();
               pr.resolve();
     public static void main(String[] args) {
          MyPatternResolver mpr = new MyPatternResolver(args[0], args[1]);
     public class PatternResolver {
          private String match, replace;
          private File source;
     public PatternResolver(String s1, String s2, File f) {
          this.match = s1;
          this.replace = s2;
          this.source = f;
     public File resolve() {
          File fout = null;
          try {
     //Create a file object with the file name in the argument:
     fout = new File(sourceFile.getName() + "_");
     //Open and input and output stream
     FileInputStream fis = new FileInputStream(sourceFile);
     FileOutputStream fos = new FileOutputStream(fout);
     BufferedReader in = new BufferedReader(new InputStreamReader(fis));
     BufferedWriter out = new BufferedWriter(new OutputStreamWriter(fos));
     // The find and replace statements
     Pattern p = Pattern.compile(match);
               Matcher m = p.matcher(replace);
               //Debugging Info
               System.out.println("Match value = " + match + " Replace value = " + replace);
               //Debugging Complete
               String aLine = null;
               while((aLine = in.readLine()) != null) {
               m.reset(aLine);
               //Make replacements
               String result = m.replaceAll(replace);
               out.write(result);
          out.newLine();
               in.close();
               out.close();
          } catch (Exception e) {
               e.printStackTrace();
return fout;

If your aim is to learn about regex, then its okay.
Otherwise you might want to check the utility "sed" (stream editor) which does something similar what you are up to. It is a POSIX (.i.e. UNIX) utility, but it is available (in several versions) for other platforms (including Windows) too. (Cf. Cygnus or Mingw).

Hoe to get the input file componets value

hi ,
i have a input file component and a command button in my jspx.
i wrote a method for the command button which needs the value in the input file component.
both the methods inputFile1.getValue() and inputFile1.getSubmittedValue() is returning null for me.
when i browse some file and i click on the button the field is getting reset. i mean i am losing the browsed file.

That isn't an input file. An input file is one that the user is uploading to the application server. What you seem to be asking is how to get an audio file that is already on the application server to play.
On the other hand, you might be asking how to combine the two operations - upload the file, then play it. So in the solutions you've been given so far, the UploadedFile object has methods to tell you what is in the file and a getInputStream method to get the data in the file as an input stream. Now what you need is a correct value for the objectMedia's source property. This needs to be a URI for a file on the application server - a filename, but in relation to your application's base directory. Take the inputStream and write it as a file on your application server, and then set the objectMedia's source to that file's name.
You may also need to consider a clean-up operation to delete the file when the user is done with it, unless you WANT it saved permanently on the application server. The other alternative is to play the file directly from it's input stream, but you won't be able to use an objectMedia component to do this.

Print to file problem (output size does not alter the user file measures)

Hi all,
as I'm using LR 2.2 (on Win XP) as trial version you can see that I'm a newbie to the programme which I like every day better as I step deeper into it.
I fought my way through organizing and developing my photos but now I have problems with the print module. I want to print the photo to a file (jpg) and therefore I am really happy about the new print to file option.
My understanding was, that when I choose the option of user file measures in the print to file module then all other settings (paper and printer settings as well as paper and layout settings) where sort of "overruled". Although I changed some of the other settings (for example paper setting in the printer dialog to DIN A 6) the idea was to get prints of the dimension 105.13 mm x 148.17 mm (DIN A6). This picture size is therefore my user file measures setting.
But it seems that I missed some important settings because I get pictures which are of the same size like the original photos: 43.8 cm x 61.7 cm and therefore much to big.
I would be pleased if someone could point out where my mistake is rooted.
THX!
Jens David

First of all thanks for the message.
But my problem is that neither of the two ways is working properly. Perhaps there was some kind of misunderstanding because I didn't used the official terms.
I specified the page size setting in the page setup dialog to DIN A6 AND I (tried to) override this by using the Custom file dimensions in the Print Job Section; there I used as well the DIN A6 dimensions of 105.13 mm x 148.17 mm.
Nonetheless my output file retains its original file dimensions.
I think I still need some ideas where the (or my) problem is rooted.
THX in advance.
JD

Image Capture - Can't set output size or jpeg options

I upgraded to SL and found out that I now have to use Image Capture instead of HP ScanPro on my OfficeJet 5510. In ScanPro, after the preview scan, I could select an area to be scanned, specify a width for the output size in pixels and let ScanPro calculate the height, and scan to a jpeg file specifying the jpeg quality as medium. Image Capture does not allow these settings. Are there any Image Capture options that are hidden somewhere or is there any other way to scan in SL?

I am having the same issue with Image Capture as well. It's not just with my JPG settings, it's with all scanned document using the document feeder. I use a canon MF4370dn. I'm attempting to scan a 20 page document to PDF and it will not allow me to set the output size, there's an option there, just will not allow me to set it (it stays blank). So when I scan I get a very small pixel on the page (about 1/2" by 1/2" on each page, nothing else is scanned in. Weird, any help?

Setting the files original size in ZipEntry

I need to create a ZipEntry with the correct original size. I've tried setting it using setSize() but it gets ignored.
I've figured out that the reason it gets ignored is because I haven't specified the CompressedSize and the CRC value as well... .mental!
If I do the compression in 2 passes, I can find out the compressed size but where on earth can I get the CRC value from? The CRC value is private in the ZipOutputstream.
I'm really stuck can anyone give me a hand to work out this madness.

If you are deflating, the header is set correctly automatically. Evidence:
import java.io.*;
import java.util.Date;
import java.util.zip.*;
public class ZipFile
     public void zipUp(File folder, File file) throws IOException
          ZipOutputStream zip = new ZipOutputStream(new FileOutputStream(file));
          addFolderToZip("", folder, zip);
          zip.flush();
          zip.close();
     private void addFolderToZip(String path, File folder, ZipOutputStream zip) throws IOException
          File[] fileList = folder.listFiles();
          if (fileList == null)
               return;
          for (File file : fileList)
               addToZip(folder.getPath(), file, zip);
     private void addToZip(String path, File file, ZipOutputStream zip) throws IOException
//          System.out.println("addToZip path="+path+" file="+file);
          ZipEntry     entry = new ZipEntry(file.getPath());
          entry.setMethod(ZipEntry.DEFLATED);
          // entry.setMethod(ZipEntry.STORED);
          entry.setTime(file.lastModified());
          zip.putNextEntry(entry);
          if (file.isDirectory())
               addFolderToZip(path, file, zip);
          else
               // Transfer bytes from in to out
               int len;
               FileInputStream in = new FileInputStream(file);
               byte[] buf = new byte[4096];
               while ((len = in.read(buf)) > 0)
                    zip.write(buf, 0, len);
               System.out.println("wrote entry name="+entry.getName()+"; crc=0x"+Long.toHexString(entry.getCrc())+"; size="+entry.getSize()+"; csize="+entry.getCompressedSize()+"; method="+entry.getMethod()+"; mtime="+new Date(entry.getTime()));
     public void     unzip(InputStream in) throws IOException
          ZipInputStream     zin = new ZipInputStream(in);
          ZipEntry     entry;
          byte[] buffer = new byte[8192];
          while ((entry = zin.getNextEntry()) != null)
               int     count;
               while ((count = zin.read(buffer)) > 0)
               // NB the fields in the ZipEntry are only available +after+ the entry data has been read.
               // This is because the metadata follows the data in the Zip format, as you would expect.
               System.out.println("read entry name="+entry.getName()+"; crc=0x"+Long.toHexString(entry.getCrc())+"; size="+entry.getSize()+"; csize="+entry.getCompressedSize()+"; method="+entry.getMethod()+"; mtime="+new Date(entry.getTime()));
          zin.close();
     public static void     main(String[] args) throws IOException
          File     file = new File("output.text");
          ZipFile     zf = new ZipFile();
          zf.zipUp(new File("build"), file);
          zf.unzip(new FileInputStream(file));
}

I recently set up multiple accounts and when I was trying to figure out how to share files I messed up something in my documents. Everytime I open a doc from the ADMIN account, a box pops up that says "The file is not in the correct format" how to fix?

I recently set up multiple accounts on my imac, When I was trying to figure out how to share the documents I must have done something wrong. When logged into the Admin account, I open up any document and I get a message box that says, "The Document could not be opened. The file isn't in the correct format. The file might be corrupted, truncated, or in an unexpected format." What did I do and how do I fix it?

Without knowing what you did it is impossible to give advice on how to correct it.
If these were files you copied over from some other system then just Re-Copy them replacing the ones that are corrupted.
Other then that I suggest you Wipe the drive and start over with a clean reinstall of the OS and programs. Then if you want to share files to All Accounts place those files in a folder in the ROOT of the drive.

How do I get the byte size of a server file before sending output via HTTP?

I need to get the byte size of the file prior to streaming it. I can't seem to find a class/method I need. Basically, I have the path c:\\tomcat\\webapps\\documents\\sample.pdf in the servlet, I was hoping I could just use something from the File class but I couldn't find anything that seems to do the trick?
thanks, in advance,
Chuck

maybe the source of the problem will help...I am trying to stream a PDF to IE and a blank page is being generated although all other file type work.
I have found a lot of answers in the forum but no specific code examples. Here's what I have so far from picking through threads in here (can someone please show me how to get the byte size of the file so that I can assign it to the method response.setContentLength();?):
String CONTENT_TYPE = " ";
     String target = " ";
public void doGet(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException {
     StringBuffer buf = new StringBuffer();
     HttpSession session = request.getSession();
     String file = request.getParameter("filename");
     target = file;
     int end = file.length();
int beg = end-2;
     String type = file.substring(beg, end);
     if (type.equals("DOC")){
          CONTENT_TYPE = "application//vnd.msword";
     }else if (type.equals("XLS")){
          CONTENT_TYPE = "application//vnd.x-excel";
     }else if (type.equals("PPT")){
          CONTENT_TYPE = "application//vnd.ms-powerpoint";
     }else if (type.equals("PDF")){
          CONTENT_TYPE = "application//vnd.x-pdf";
     }else if (type.equals("MPP")){
          CONTENT_TYPE = "application//vnd.ms-project";
     }else if (type.equals("ZIP")){
          CONTENT_TYPE = "application//ZIP";
     }else if (type.equals("TXT")){
          CONTENT_TYPE = "text//plain";
     }else {
          CONTENT_TYPE = "text//html";
     //File f = new File(file);
     //int l = f.length();
     response.setContentLength(l); <----- supposedly this fixes my problem but I don't know how to get the byte szie of the file in an integer??
     // reset the response
     response.reset();
     response.setContentType(CONTENT_TYPE);
     try{
     // Get streams
     FileInputStream fileInputStream = new FileInputStream(target);
     ServletOutputStream servletOutputStream = response.getOutputStream();
     // Init byte count and array
     int bytesRead = 0;
     byte byteArray[] = new byte[4096];
     // Read in bytes through file stream, and write out through servlet stream
     while((bytesRead = fileInputStream.read(byteArray)) != -1) {
     servletOutputStream.write(byteArray, 0, bytesRead);
          servletOutputStream.flush();
     // Flush and close streams
     servletOutputStream.flush();
     servletOutputStream.close();
     fileInputStream.close();
     } catch (Exception e) {
     System.out.println(e.toString());

Setting up FileName for Output file in SendPort

Hi - I have a requirement setting up FileName in output file. For instance say, whatever I receive in the 'FathersName' field that Output File should be with that File Name.
For e.g. if data received in FathersName field is JOHN, output file name should be JOHN.xml
I am using File Adapters on Receive and send side.
Can this be achieved just by Messaging Scenario or do I need to implement this using Orchestration ?
If so, please advise on how to do this ?
e.
MBH

To achieve this, you will have to set your filename value on one of the Context Properties available as a File Adapter macro. For example FILE.ReceivedFileName is mapped to the %SourceFileName% macro.
You have several options to do this:
Set FILE.ReceivedFileName in an Orchestration. It does not have to be Promoted.
Write the Property ReceivedFileName in namespace
http://schemas.microsoft.com/BizTalk/2003/file-properties in a Custom Pipeline Component.
If FathersName can be used in the file name unmodified, you set FathersName as a Promoted Property on the schema and Promote directly to FILE.ReceivedFileName.
For 1 & 2, you will have to extract FathersName somehow, such as a distinguished field.
A Custom Pipeline Component or direct Promotion are the only way to achieve this in Messaging only.

How do I set a fixed page size in Muse so that the window always stays the same size

how do I set a fixed page size in Muse so that the window always stays the same size

Hi Aish & thanks for responding;
I would like the window size to stay the same for the entire site and not be
able to scale to drag & scale it. ie 950 pixels x 500 pixels.
Thanks,
JB
On 12/4/14 3:30 PM, "Aishvarya Raj Rastogi" <[email protected]>

Setting a fix file output size regardless of input file..How?

Similar Messages

Maybe you are looking for