Why I cannot get payroll result value ?

Expert,
In EBS Payroll R12, I define two elements A and B. A has priority 1500, B has priority 3500. So A will be processed ahead of B. I write a pl/sql package to calculate B, and attach the package to B through formula result. In the package, I will use "Pay value" of A, the logic can be abstracted as " A-Pay value * 0.05". However, the result of B is not my expected. I track my package and find the program doesn't get the Pay Value. I am sure my sql statement is right. So my conclusion is for one assignment calculation, these elements payroll result will be written back to DB together rather than one by one, right?
For my case, it I want to use the pay value of elements which have been calculated, how to do? Please give me some advice.
Thanks in advance.

Dear thierry,
Thanks for your kindly help. I follow your hints to modify my fast formula of B as below:
Cal_B:
dummy=A_BALANCE_ASG_RUN /* A_Balance will contain element A*/ /* a new line added here */
v_rtvl=CAL_B_external_F /* It is formula function, which will contain external PLSQL call. The plsql will use the Pay value of A */
return v_rtvl
Per my understanding, after calling statement "dummy=A_BALANCE_ASG_RUN", the relevant pay result of A should be flushed to DB.
unfortunately, when I process my payroll, the result still remains unchange. It seems that CAL_B_external_F cannot get the "Pay value" of A
If I modify fast formula as below:
Cal_B:
v_rtvl=A_BALANCE_ASG_RUN
return v_rtvl
I can get v_rtvl whose value is equal to A_BALANCE_ASG_RUN. It seems the value of A_BALANCE_ASG_RUN can be captured in the fast formula.
So, How do I understand your hints as below:
"A element_A_asg_run in your second fast formula, before calling the plsql, can do the trick, eventually."
I am eager to your help.
Regards,
Michael
Edited by: Gang2 on Mar 22, 2009 10:45 PM

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