Number Return is not in correct format

Hi,
I have oracle 10 R2 On windows.
I am retriving sum of amount from one of my table and and due to huge amount it showing + sign in that like :-
select sum(amount) from t;
Output :
2.7201E+10 I dont need these . and E+ in the number. Please suggest how i can write a query.
Regards,
Chanchal Wankhade.

This is a formatting issue of the client. In SQL Plus See this example.
Connected to:
Oracle Database 10g Enterprise Edition Release 10.2.0.5.0 - 64bit Production
With the Partitioning, OLAP, Data Mining and Real Application Testing options
SQL> select 9999999999 no from dual
2 /
        NO
9999999999
SQL> select 99999999999999999999 no from dual
2 /
                  NO
          1.0000E+20
SQL> column no format 99999999999999999999
SQL>
SQL> select 99999999999999999999 no from dual
2 /
                   NO
99999999999999999999
You need to use the correct column format in the client to get the correct output.

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Hi Max,
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I need message like below one.
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Hi,
I'm experiencing difficulties with the CUCM Mobility (Single Number Reach) function.
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The version of call manager is 8.6.2.20000-2.

I did a debug isdn q931 on the voice router which is connected to the PRI circuit.
A couple of test calls later and this is the output I got:
Jun 28 08:34:15.737: ISDN Se0/0/0:15 Q931: RX <- SETUP pd = 8 callref = 0x0E5A
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Hello everyone.
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Here is the class code.
using System;
using System.Collections.Generic;
using System.Text;
using ExceptionLogger;
using Oracle.DataAccess.Client;
using System.Configuration;
using System.Data;
namespace OracleExceptionLogger
/// <summary>
/// Oracle version of exception logger.
/// </summary>
public class ExceptionLogger : IExceptionLogger
private OracleConnection _connection;
private string _connectionString;
private string _sqlInsertCmd =
@"insert into ips_exception_log" + "\n" +
@" (id" + "\n" +
@", log_date_time" + "\n" +
@", form" + "\n" +
@", source" + "\n" +
@", message" + "\n" +
@", querystring" + "\n" +
@", targetsite" + "\n" +
@", stacktrace" + "\n" +
@", referrer" + "\n" +
@" )" + "\n" +
@"values (ips_log_seq.nextval" + "\n" +
@", :log_date_time" + "\n" +
@", :form" + "\n" +
@", :source" + "\n" +
@", :message" + "\n" +
@", :querystring" + "\n" +
@", :targetsite" + "\n" +
@", :stacktrace" + "\n" +
@", :referrer" + "\n" +
@" )" + "\n" +
@"returning id" + "\n" +
@"into :returnId";
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/// Initializes <c>ExceptionLogger</c>.
/// </summary>
public ExceptionLogger()
ExceptionLoggerConfigSection section = ExceptionLoggerConfigSection.GetSection();
_connectionString = section.ConnectionString;
connection = new OracleConnection(connectionString);
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/// Saves an entry in the database.
/// </summary>
/// <param name="data">Entry to save.</param>
/// <returns>EventId of ExceptionLogData that was saved.</returns>
public long Save(ExceptionLogData data)
long eventId = 0;
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_connection.Open();
try
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if (result != 1)
throw new Exception("Log entry data " + data.ToString() + " wasn't saved properly.");
finally
_connection.Close();
return eventId;
}

Ah, I've found it.
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LENGTH function for a large number returns 40 not the number of digits

In SQL*Plus:
SQL> select length(12345678901234567890123456789012345678901234567890)lngth
2 from dual;
LNGTH
40
SQL> select length('12345678901234567890123456789012345678901234567890')lngth
2 from dual;
LNGTH
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Additional reason.
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12345678901234567890123456789012345678900000000000
SQL> select length(12345678901234567890123456789012345678901234567890) numlen from dual;
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SQL> select to_char(12345678901234567890123456789012345678901234567890) numlen from dual;
NUMLEN
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SQL> select length(to_char(12345678901234567890123456789012345678901234567890)) numlen from dual;
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                                                40
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3 num from dual;
NUM
12345678901234567890123456789012345678900000000000
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2                '09000000000000000000000000000000000000000000000000'))
3 num from dual;
                                               NUM
                                                51
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2                'fm09000000000000000000000000000000000000000000000000')
3 num from dual;
NUM
12345678901234567890123456789012345678900000000000
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2                'fm09000000000000000000000000000000000000000000000000'))
3 num from dual;
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Here is the code:
## begin code
OracleConnection dbc = new OracleConnection();
string sConnectString = "User Id=" + username.ToString() + ";Password=" + password.ToString() + ";Data Source=" + tnsname.ToString();
dbc.ConnectionString = sConnectString.ToString();
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dbc.Open();
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## end code
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Eric S.

Hello,
well, i got a message "...string not wellformed format...", too.
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For example, two code snippets:
As datasource i use <Server>:<Port>/<Instance>
try
string FDsn ="User Id="+FDbUser+";Password="+FDbPwd;
FDsn +=";Data Source=wth5:1521/Ora9.wth5";
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FConn.Open();
if (FConn.State == ConnectionState.Open )
FConn.Close();
catch (Exception ex)
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by using
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i connect to an OraExpress database on the same machine.
My Oracle.dataAccess.dll ist the newest, 10.2.... and it runs under Framework 1.1.x and Framework 2.x
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Hi,
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Hi,
Let me try.
This is your formula.
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Regards,
Amit

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Don't do DHCP based binding, configure it manually.
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Number Return is not in correct format

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