Query for employee information

Question

Good afternoon.
I'm having trouble on how to determine the employee department, division, organization as well as the company.
Any idea guys??
Thank you,
Rey

Answer 1

Hi Vignesh,
This is my query.. our user gave me this navigation(Global Super HRMS Manager > Work Structures > Organization > Description) for the department, division etc. but couldn't find a relationship between employee record and this navigation.
SELECT
hr_general.decode_position_latest_name(assignment.position_id),
sck.concatenated_segments,
grp.group_name,
  people.employee_number,
  people.last_name,
  people.first_name,
  people.middle_names,
  hr_general.decode_position_latest_name(assignment.position_id),
  org_struc.d_parent_name,
  sck.concatenated_segments,
  org.NAME,
  locations.location_code LOCATION,
  jobs.NAME JobName,
  hr_general.decode_lookup('EMPLOYEE_CATG', assignment.employee_category),
  sck.segment1,
  people.person_id,
  assignment.organization_id
FROM per_people_f people ,
  per_all_assignments_f assignment ,
  hr_locations_all_tl locations ,
  per_org_structure_elements_v org_struc,
  per_jobs_tl jobs ,
  per_grades_tl grade,
  per_all_organization_units org,
  HR_SOFT_CODING_KEYFLEX sck,
  PAY_PEOPLE_GROUPS grp
WHERE people.person_id          = assignment.assignment_id
AND people.business_group_id    = assignment.business_group_id
AND assignment.location_id      = locations.location_id
AND assignment.soft_coding_keyflex_id = sck.soft_coding_keyflex_id
AND assignment.organization_id          = org.organization_id
AND sck.segment1 = org_struc.organization_id_child
AND assignment.job_id           = jobs.job_id
AND assignment.people_group_id = grp.people_group_id
AND assignment.grade_id         = grade.grade_id
AND assignment.assignment_type IN ('E','C')
AND SYSDATE BETWEEN people.effective_start_date AND people.effective_end_date
AND SYSDATE BETWEEN assignment.effective_start_date AND assignment.effective_end_date
AND assignment.business_group_id=people.business_group_id
ORDER BY people.last_name, people.first_name asc;